(x-1/2)² + (y-3/2)² = 4/9
For any circle in the standard form (x-h)² + (y-k)² = r², the center is at (h, k) and the radius is r.
In the case of our equation here. the center is at (1/2, 3/2) with a radius of 2/3.
X = -4
It can also be written as x + 4 = 0
Answer:HMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMM
Step-by-step explanation:
never saw that before
The education is (x-h)^2 + k ands the vertex is (h,k)
