Answer:
Step-by-step explanation:
We are told the school sold raffle tickets, and each ticket has a digit either 1, 2, or 3. The school also sold 2 tickets with the number 000.
Therefore we have the following raffle tickets:
123
132
213
231
312
321
000
000
From the given information, we can deduce that the school sold 8 tickets and only one ticket can contain the number arrangement of 123, but 000 appeared twice.
Probability of 123 to be picked=
1/8 => 0.125
Probability of 000 to be picked=
2/8 => 0.25
Since the probability of 000 to be picked is greater than 123, a ticket number of 000 is more likely to be picked
Answer:
9
Step-by-step explanation:
7r+18=r²
r²-7r-18=0
factorizing
r²+2r-9r-18=0
r(r+2)-9(r+2=0
(r-9)(r+2)=0
r-9=0
r=9
check
(r²)=(9*9)=81
7r+18=7(9) + 8=81
X + y + z = 32 * 3
27 + 27 + x = 96
X = 54
2x = 108
Average of x and 2x = (54+108) / 2 = 164 / 2 = 82
Average of X and 2X = 82
Step 1:
First, let's order the number from least to greatest.
A. -0.31
B. -0.33
C. -0.38
D. -0.29
We could see that A, B, and C's numbers are already from least to greatest, so all we have to do is to move -0.29 (D) up to the top, since -0.29 is the number with the lowest value.
C. -0.38
B. -0.33
A. -0.31
D. -0.29
Step 2:
Let's look at the four number lines. Remember that we already organized the numbers from least to greatest, so the order they go in on the number line is: C, B, A, and D. Since Line C and D Don't follow that rule, we know those are not our answers. Also on line B, C is on the left of -0.4, but C's value is less than -0.4, so B is wrong. We are left with line A.
Line A: C. -0.38, B. -0.33, A. -0.31, D. -0.29
Our answer: Line A
