What type of angle pair is Angle ACE and BCE?

Mathematics

1 answer:

Jobisdone [24]3 years ago

6 0

if ACE line is linear so you can say BCA angle plus BCE equal to 180 degree

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3 years ago

QUICK HELP PLEASE!!!!

Andrew [12]

h = 2t - d

multiply both sides by 2 to eliminate the fraction

2t = d + h

subtract d from both sides

2t - d = h ⇒ h = 2t - d

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3 years ago

Pioneer company has given an aptitude test to 71 potential job applicants. The test score had an average of 81 and a standard de

Agata [3.3K]

Answer:

Follows are the solution to the given points:

Step-by-step explanation:

In point A:

$\to df = n - 1 = 71-1= 70$

In point B:

$\to t = \frac{(x -X)}{s} = \frac{(93-81)}{8} = \frac{12}{8}= 1.5$

In point C:

For df = 70, the top 5% critical t score

tcrit = 1.666914479

Thus,

$\to 1.666914479 = \frac{(x - 81)}{8}\\\\\to 1.666914479 \times 8 = (x - 81)\\\\\to 13.335315832 = (x - 81)\\\\\to 13.335315832 +81 =x \\\\\to x= 94.335315832$

In point D:

For df = 70, the top 5% critical t score

tcrit = -1.666914479

$\to -1.666914479 = \frac{(x - 81)}{8}\\\\\to -1.666914479 \times 8= (x - 81)\\\\\to -13.335315832= (x - 81)\\\\\to -13.335315832+81 = x \\\\\to x = 67.664684168\\\\$

In point E:

The lower cutoff is 0.10 in the center, which would be around 80 %. The critical point therefore is

tcrit = -1.293762898

$\to -1.293762898 = \frac{(x-81)}{8}\\\\\to -1.293762898 \times 8= (x-81) \\\\\to -1.293762898 \times 8= (x-81) \\\\\to -10.350103184=x-81\\\\\to -10.350103184+81=x\\\\\to x=70.649896816$