<u>Answer:</u>
<em>int fNumber,scndNumber = -1, </em>
<em>dup = 0;
</em>
<em>do {
</em>
<em>cin >> fNumber;
</em>
<em>if ( scndNumber == -1) {
</em>
<em>scndNumber = fNumber;
</em>
<em>}
</em>
<em>else {
</em>
<em>if ( scndNumber == fNumber )
</em>
<em>duplicates++;
</em>
<em>else
</em>
<em>scndNumber = fNumber;
</em>
<em>}
</em>
<em>} while(fNumber > 0 ); </em>
<em>cout << dup;
</em>
<u>Explanation:</u>
Here three variables are declared to hold the first number which is used obtain all the inputs given by the user, second number to hold the value of <em>last encountered number and “dup” variable to count the number of duplicate values.</em>
<em>“Do-while”</em> loop help us to get the input check whether it is same as previous input if yes then it <em>adds to the duplicate</em> value otherwise the new previous value if stored.
Btw..which dtadium do u want cricket or football!?
You have to destroy the hard drive as it is like a memory for the computer so it can never be deleted
Answer:
print("Let's play Silly Sentences!")
print(" ")
name=input("Enter a name: ")
adj1=input("Enter an adjective: ")
adj2=input("Enter an adjective: ")
adv=input("Enter an adverb: ")
fd1=input("Enter a food: ")
fd2=input("Enter another food: ")
noun=input("Enter a noun: ")
place=input("Enter a place: ")
verb=input("Enter a verb: ")
print(" ")
print(name + " was planning a dream vacation to " + place + ".")
print(name + " was especially looking forward to trying the local \ncuisine, including " + adj1 + " " + fd1 + " and " + fd2 + ".")
print(" ")
print(name + " will have to practice the language " + adv + " to \nmake it easier to " + verb + " with people.")
print(" ")
print(name + " has a long list of sights to see, including the\n" + noun + " museum and the " + adj2 + " park.")
Explanation:
Got it right. Might be a longer version, but it worked for me.
