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Artyom0805 [142]
3 years ago
12

The graph shows the cost for each lawn that is mowed.

Mathematics
2 answers:
Ugo [173]3 years ago
5 0
My answer would be B. i know this because i took the test and had this correct. hope this helps everyone looking for it
mojhsa [17]3 years ago
3 0
The rate of change of a graph is given by the y value divided by the x value.

Given that the y-axis is labelled cost (dollars) and that the x-axis is labelled lawns mowed.

Therefore, the rate of change represents the cost per lawn mowed.
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Anna wants to take fitness classes. She compares two gyms to determine which would be the best deal for her. Fit Fast charges a
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Fit Fast: a set feet per class => y = Ax

Stepping Up: a monthly fee plus an additioal fee per class => h = Bx + C

You can discard the second and the fourth systems because  they do not have the form established from the statement.

The first system produce an obvious result given that is represents an option that is always better than the other 5.5x will be lower than 7.5x + 10 for any positive value of x, and so there is no need to make any comparission.

The third system is

y = 7.5x and y = 5.5x + 10 which need to be solved to determine when one rate is more convenient than the other.

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3 years ago
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Which describes the median set of data
blagie [28]

In a set of data, to find the median you first have to order your data from greatest to least then find the center or (median) of your data. E is your answer.

3 0
2 years ago
One stats class consists of 52 women and 28 men. Assume the average exam score on Exam 1 was 74 (σ = 10.43; assume the whole cla
Svetllana [295]

Answer:

(A) What is the z- score of the sample mean?

The z- score of the sample mean is 0.0959

(B) Is this sample significantly different from the population?

No; at 0.05 alpha level (95% confidence) and (n-1 =79) degrees of freedom, the sample mean is NOT significantly different from the population mean.

Step -by- step explanation:

(A) To find the z- score of the sample mean,

X = 75 which is the raw score

¶ = 74 which is the population mean

S. D. = 10.43 which is the population standard deviation of/from the mean

Z = [X-¶] ÷ S. D.

Z = [75-74] ÷ 10.43 = 0.0959

Hence, the sample raw score of 75 is only 0.0959 standard deviations from the population mean. [This is close to the population mean value].

(B) To test for whether this sample is significantly different from the population, use the One Sample T- test. This parametric test compares the sample mean to the given population mean.

The estimated standard error of the mean is s/√n

S. E. = 16/√80 = 16/8.94 = 1.789

The Absolute (Calculated) t value is now: [75-74] ÷ 1.789 = 1 ÷ 1.789 = 0.559

Setting up the hypotheses,

Null hypothesis: Sample is not significantly different from population

Alternative hypothesis: Sample is significantly different from population

Having gotten T- cal, T- tab is found thus:

The Critical (Table) t value is found using

- a specific alpha or confidence level

- (n - 1) degrees of freedom; where n is the total number of observations or items in the population

- the standard t- distribution table

Alpha level = 0.05

1 - (0.05 ÷ 2) = 0.975

Checking the column of 0.975 on the t table and tracing it down to the row with 79 degrees of freedom;

The critical t value is 1.990

Since T- cal < T- tab (0.559 < 1.990), refute the alternative hypothesis and accept the null hypothesis.

Hence, with 95% confidence, it is derived that the sample is not significantly different from the population.

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Answer:

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The sequence is in a decreasing order of -2 for the next sequence.

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