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3 years ago

5

Emily needs to buy fabric to make curtain panels for her windows. Each panel will be 4 feet long and 1/2 foot wide. Each piece o

f fabric that she can buy is 4 feet long and 2 feet wide . How many panels can she make from i piece of fabric?

2 answers:

makkiz [27]3 years ago

8 0

Each panel is 4 ft long and 1/2 ft wide

The piece of fabric is 4 ft long and 2 ft wide

So she can therefore fit 4 panels into this. We can calculate this by area
4*1/2=2ft^2

4x2=8ft^2

So 4*2 =8

mafiozo [28]3 years ago

3 0

The pieces of fabric are already the correct length, so it is just a matter of how many panels will fit into one piece of fabric. 2/(1/2) = 4, so she can make 4 panels from 1 piece of fabric.

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What is the answer need it

denis-greek [22]

Answer:

$\frac{7}{10} |$

Step-by-step explanation:

STEP 1:

2/3 + 7/10 = ?

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(2/3, 7/10) = 30

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

$(\frac{2}{3}$ * $\frac{10}{10})$ + $(\frac{7}{10} * \frac{3}{3})$ = ?

Complete the multiplication and the equation becomes

$\frac{20}{30} + \frac{21}{30}$

The two fractions now have like denominators so you can add the numerators.

Then:

$\frac{20+21}{30} = \frac{41}{30}$

This fraction cannot be reduced.

The fraction 41/30

is the same as

41 divided by 30

Convert to a mixed number using

long division for 41 ÷ 30 = 1R11, so

41/30 = 1 11/30

Therefore:

2/3+7/10= 1 11/30

STEP 2:

41/30 + -2/3

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(41/30, -2/3) = 30

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

$(\frac{41}{30} *\frac{1}{1} ) + ( \frac{-2}{3} * \frac{10}{10} )$

The two fractions now have like denominators so you can add the numerators.

Then:

$\frac{41+-20}{30} = \frac{21}{30}$

This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 21 and 30 using

GCF(21,30) = 3

$\frac{21/3}{30/3} =\frac{7}{10}$

Therefore:

$\frac{41}{30} + \frac{-2}{3} =\frac{7}{10}$ |

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2 years ago

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Answer:

Total amount = R5112

Step-by-step explanation:

Let the cooks be C.

Let the waiters be W.

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Number of waiters, W = 3

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C = 36 * R36 = R1296

b. To find the amount earned by each waiter;

W = 30 * R28 = R840

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3 years ago

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Alina [70]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.

Mice21 [21]

Answer:

<em>LCM</em> = $8y^{4}(y+ 10)^{2}(y + 8)$

Step-by-step explanation:

Making factors of $8y^{6}+ 144y^{5}+ 640y^{4}$

Taking $8y^{4}$ common:

$\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)$

Using <em>factorization</em> method:

$\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times 4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)$

Now, Making factors of $2y^{4} + 40y^{3} + 200y^{2}$

Taking $2y^{2}$ common:

$\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)$

Using <em>factorization</em> method:

$\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10) ............ (2)$

The underlined parts show the Highest Common Factor(HCF).

i.e. <em>HCF</em> is $2y^{2} (y+ 10)$ .

We know the relation between <em>LCM, HCF</em> of the two numbers <em>'p' , 'q'</em> and the <em>numbers</em> themselves as:

$HCF \times LCM = p \times q$

Using equations <em>(1)</em> and <em>(2)</em>: $\Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)$

Hence, <em>LCM</em> = $8y^{4}(y+ 10)^{2}(y + 8)$

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rodikova [14]

What kind of problems or what are you trying to ask?

8 0

3 years ago