Question: If the subspace of all solutions of
Ax = 0
has a basis consisting of vectors and if A is a matrix, what is the rank of A.
Note: The rank of A can only be determined if the dimension of the matrix A is given, and the number of vectors is known. Here in this question, neither the dimension, nor the number of vectors is given.
Assume: The number of vectors is 3, and the dimension is 5 × 8.
Answer:
The rank of the matrix A is 5.
Step-by-step explanation:
In the standard basis of the linear transformation:
f : R^8 → R^5, x↦Ax
the matrix A is a representation.
and the dimension of kernel of A, written as dim(kerA) is 3.
By the rank-nullity theorem, rank of matrix A is equal to the subtraction of the dimension of the kernel of A from the dimension of R^8.
That is:
rank(A) = dim(R^8) - dim(kerA)
= 8 - 3
= 5
Answer:
A= 7 11/12 or 7.916 or 95.12
B= 4 1/8 or 4.125 or 33/8
C= 12 4/5 or 12.8 or 64/5
The answer is B) 1/4.
There are 2 outcomes in his tree that have all coins with the same side up: HHH and TTT. There are 8 total outcomes. This makes the probability 2/8 = 1/4.
Those are vertical angles,so they are equal
150=5m
m=150/5
m=30
