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Sholpan [36]
3 years ago
7

Math???????????.../?

Mathematics
2 answers:
Shalnov [3]3 years ago
8 0
8.05 \cdot 10^8 - 9.16 \cdot 10^6 \\\\ =10^6(8.05 \cdot 10^2-9.16) \\\\ =10^6(805-9.16) \\\\ =10^6(795.84) \\\\ =795.84 \cdot 10^6 \\\\ = 7.96 \cdot 10^8\ kilograms
Trava [24]3 years ago
7 0

Answer:

Math

Step-by-step explanation:

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Help me pleaseeeeeeeee
Umnica [9.8K]
Because it’s an equalacteral it should be 60
7 0
2 years ago
Please answer the equation in the attachment.
MariettaO [177]

Answer:

the missing value is 9.33.

Step-by-step explanation:

given,

length (l) = 3x+2

breadth (b) = 4

perimeter(P) = 68 cm

now,

P = 2(l+b)

or, 68 = 2× ( 3x+2+4)

or, 68 = 2× ( 3x+ 6)

or, 68 = 6x+12

or, 68 - 12= 6x

or, 56 = 6x

or, 6x = 56

or, x = 56/6

or, x = 9.33

7 0
3 years ago
The area of a round table in Kim’s living room is 201 square inches. What is the circumference of the round table, to the neares
svetoff [14.1K]
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3 0
3 years ago
Weights were recorded for all nurses at a particular hospital, the mean weight for an individual nurse was 135 lbs. with a stand
Aloiza [94]
Given:
population mean, μ =135
population standard deviation, σ = 15
sample size, n = 19

Assume a large population, say > 100,
we can reasonably assume a normal distribution, and a relatively small sample.
The use of the generally simpler formula is justified.

Estimate of sample mean
\bar{x}=\mu=135

Estimate of sample standard deviation
\s=\sqrt{\frac{\sigma^2}{n}}
=\sqrt{\frac{15^2}{19}}=3.44124  to 5 decimal places.

Thus, using the normal probability table,
P(125
=P(\frac{125-135}{3.44124}
=P(-2.90593
=P(Z
=P(Z

Therefore 
The probability that the mean weight is between 125 and 130 lbs 
P(125<X<130)=0.0731166-0.0018308
=0.0712858



3 0
3 years ago
Which are acceptable names for the plane?
BartSMP [9]
B and D are correct. D is C and A aren't correct because a plane consists of three points.
4 0
3 years ago
Read 2 more answers
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