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Sholpan [36]
3 years ago
7

Math???????????.../?

Mathematics
2 answers:
Shalnov [3]3 years ago
8 0
8.05 \cdot 10^8 - 9.16 \cdot 10^6 \\\\ =10^6(8.05 \cdot 10^2-9.16) \\\\ =10^6(805-9.16) \\\\ =10^6(795.84) \\\\ =795.84 \cdot 10^6 \\\\ = 7.96 \cdot 10^8\ kilograms
Trava [24]3 years ago
7 0

Answer:

Math

Step-by-step explanation:

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How many books were read in all? <br>A. 150 <br>B.156 <br>C. 158 <br>D. 160 <br>E. 162​
Anarel [89]

Answer:

D: 160

Step-by-step explanation:

Fifth graders read 68, which is easy to see.  Fourth graders read between 48 and 52, the bar appears to be directly in the middle of the two lines, so we say they read 50.  Third graders read between 40 and 44, again the bar appears to be directly in the middle so we say they read 42.

42+50+68=160

8 0
3 years ago
Read 2 more answers
1 5/8 divide 1.625= what
adoni [48]

Actually:

1 5/8 simplifies to 1.625. Do 5.8 and get 0.625 then add 1. Its 1.625. So 1.625/1.625=1. Its the same thing with mixed number. (1 5/8) / 1.625 = 1

6 0
3 years ago
.Write the quadrants/axes in which the following points lie a) (2,-3) b)(0,8) c)(-1,-2) d)(4,7)
natka813 [3]

Answer:

[see below]

Step-by-step explanation:

Quadrant One has a positive value for both x and y. (+ , +)

Quadrant Two has a negative x value. (- , +)

Quadrant Three has a negative value for both x and y. (- , -)

Quadrant Four has a negative y value.  (+, -)

Therefore:

(2, -3) would be plotted in Q4. It does not lie on any axis.

(0, 8) would be on the positive y-axis. (0 is neither negative nor positive.)

(-1, -2) would be plotted in Q3.  It does not lie on any axis.

(4, 7) would be plotted in Q1.  It does not lie on any axis.

5 0
3 years ago
The level of nitrogen oxides (NOX) in the exhaust after 50,000 miles or fewer of driving of cars of a particular model varies No
Greeley [361]

Answer:

For a level of 0.0174 or more of nitrogen oxide, the probability of fleet is 0.01.              

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 0.02 g/mi

Standard Deviation, σ = 0.01 g/mi

Sample size, n = 81

We are given that the distribution of  level of nitrogen oxides is a bell shaped distribution that is a normal distribution.

Standard error due to sampling:

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{0.01}{\sqrt{81}} = 0.0011

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.01

P(X > x)  

P( X > x) = P( z > \displaystyle\frac{x - 0.02}{0.0011})=0.01  

= 1 -P( z \leq \displaystyle\frac{x - 0.02}{0.0011})=0.01  

=P( z \leq \displaystyle\frac{x - 0.02}{0.0011})=0.99  

Calculation the value from standard normal z table, we have,  

\displaystyle\frac{x - 0.02}{0.0011} = -2.326\\\\x = 0.0174

For a level of 0.0174 or more of nitrogen oxide, the probability of fleet is 0.01.

5 0
3 years ago
6. a) The mid point of a line segment is (1,-1) whose one end is (-1, -3). Find the other end. ​
Anna [14]

Answer:

Step-by-step explanation:

mid point = [(a1 + a2)/2 , (b1 + b2)]

(a1,b1) = first point

(a2,b2) = end point

Using all x coordinates

(a1 + a2)/2 = 1

(-1 + a2)/2 = 1

-1 + a2 = 2

a2 = 3

Using all y coordinates

(b1 + b2)/2 = -1

(-3 + b2)/2 = -1

-3 + b2 = -2

b2 = -1

thus end coordinate = (3, -1)

5 0
2 years ago
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