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koban [17]
3 years ago
12

Help on $3.70÷2=no clue

Mathematics
2 answers:
Harman [31]3 years ago
4 0
The answer is 1.85 because if you add. 1.85 2 times you get 3.70
Daniel [21]3 years ago
3 0
3.7/2 = 1.85
2 goes into 3 1 time.
you have a remainder of 1
That one gets a 7 after it
now you have 17
2 goes into 17 8 times
remainder of 1
bring down the 0 that's there, but is not shown because it's not important in standard form or decimals.
You get 10 and that's 5
so you have 1.85
1.85$
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Answer:

a) For this case we need that she fails the first 3 throws and the last one would be successful, so then if p represent the probability of success and 1-p the probability of fail we have this:

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b) "=1-BINOM.DIST(99,140,0.65,TRUE)"

P(X \geq 100) = 1-P(X

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And we want this probability:

P(X \geq 100) = 1-P(X

Step-by-step explanation:

Part a

For this case we need that she fails the first 3 throws and the last one would be successful, so then if p represent the probability of success and 1-p the probability of fail we have this:

(1-p)^3 p = (1-0.65)^3 (0.65)= 0.0279

Part b

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=140, p=0.65)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

For this case we want this probability:

P(X \geq 100) = 1-P(X

And we can use the following excel code:

"=1-BINOM.DIST(99,140,0.65,TRUE)"

P(X \geq 100) = 1-P(X

Part c

We need to check the conditions in order to use the normal approximation.

np=140*0.65=91 \geq 10

n(1-p)=140*(1-0.65)=49 \geq 10

So then we can use the normal approximation and we can find the mean and deviation like this:

\mu = np = 140*0.65= 91

\sigma = \sqrt{np(1-p)}= \sqrt{140*0.65(1-0.65)}=5.644

And we want this probability:

P(X \geq 100) = 1-P(X

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