These techniques for elimination are preferred for 3rd order systems and higher. They use "Row-Reduction" techniques/pivoting and many subtle math tricks to reduce a matrix to either a solvable form or perhaps provide an inverse of a matrix (A-1)of linear equation AX=b. Solving systems of linear equations (n>2) by elimination is a topic unto itself and is the preferred method. As the system of equations increases, the "condition" of a matrix becomes extremely important. Some of this may sound completely alien to you. Don't worry about these topics until Linear Algebra when systems of linear equations (Rank 'n') become larger than 2.
Answer:
3) 
4) a) 
b) 
Step-by-step explanation:
<u>Exercise 3</u>



<u>Exercise 4</u>
a) If L2 is parallel to L1, it has the same slope (gradient) ⇒ 
If L2 passes through point (3, 1):



So L2 = L1
b) If L3 is perpendicular to L1, then the slope of L3 is the negative reciprocals of the slope of L1 ⇒ 
If L3 passes through point (-5, 2):



Answer:
132 square millimeters
Step-by-step explanation:
THe <u>lateral area</u> of a rectangular prism is the side areas. That is
all 4 sides of the rectangular prism (that are rectangles each).
So, we find each side area and add them up.
The area of a rectangle is:
Area = length * width
The left side (in gray) is 9 mm x 3mm, so area:
area = 9 * 3 = 27
The right side rectangle is same, so that would have an area of:
area = 9 * 3 = 27
Now, the front side's measurement is 3 x 13, so the area is:
Area = 3 * 13 = 39
THe back is same, so the area would be:
Area = 3 * 13 = 39
<u>Total Surface Area = 27 + 27 + 39 + 39 = 132 square millimeters</u>
Answer:
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Step-by-step explanation:
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