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3 years ago

7

Mr. Lee bought 3 pounds of tomatoes for $0.90 per pound, 2 heads of lettuce for $1.10 each, and a carton of milk for $2.85. he g

ave the clerk $10. how much change should Mr. Lee receive back from the clerk?

1 answer:

miv72 [106K]3 years ago

7 0

Jsneusjsnbehddjdd hahaha

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Given g of x equals cube root of the quantity x minus 3, on what interval is the function positive?

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The function is positive when x is larger than 3, then the interval in where the function is positive is: (3, ∞)

<h3>on what interval is the function positive?</h3>

The function is positive when g(x) > 0.

Then we need to solve:

∛(x - 3) > 0

We can directly remove the cubic root, because it does not affect the sign of the argument, then:

x - 3 > 0

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2 years ago

Read 2 more answers

Which two values of x are roots of the polynomial below?<br> 3x2-3x+1

QveST [7]

Answer:

The roots are

$x=\frac{1}{6} [3+ i\sqrt{3}]$

$x=\frac{1}{6} [3- i\sqrt{3}]$

Step-by-step explanation:

we have

$3x^2-3x+1$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$3x^2-3x+1=0$

so

$a=3\\b=-3\\c=1$

substitute in the formula

$x=\frac{-(-3)\pm\sqrt{-3^{2}-4(3)(1)}} {2(3)}$

$x=\frac{3\pm\sqrt{-3}} {6}$

Remember that

$i=\sqrt{-1}$

so

$x=\frac{1}{6} [3\pm i\sqrt{3}]$

The roots are

$x=\frac{1}{6} [3+ i\sqrt{3}]$

$x=\frac{1}{6} [3- i\sqrt{3}]$

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3 years ago