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kifflom [539]
2 years ago
6

Prove (x+y)^2=x^2+2xy+y^2

Mathematics
2 answers:
ale4655 [162]2 years ago
8 0
First, you want to expand the equation so it'll be: x^2+2yx+y^2=x*2+2xy+y^2

Then you subtract y^2 from both sides: x^2+2yx+y^2-y^2=x*2+2xy+y^2-y^2

After that, you simplify: x^2+2yx=x*2+2xy

And subtract x^2+2xy from both sides: x^2+2yx-(x*2+2xy) =x*2+2xy-(x*2+2xy)

Finally, you simplify to get your final answer which is <em>x=2, x=0</em>
Scrat [10]2 years ago
3 0
Rules of exponents and the distributive property apply.
  (x+y)² = (x+y)·(x+y) . . . . . meaning of exponent of 2
  = x·(x+y) +y·(x+y) . . . . . . . distributive property
  = x·x +x·y +y·x +y·y . . . . . distributive property
  = x² +x·y +x·y +y² . . . . . . meaning of exponent of 2, commutative property of multiplication
  = x² +(1+1)·x·y +y² . . . . . . distributive property
  = x²+2xy+y² . . . . . . . . . the desired form
Thus
  (x+y)² = x²+2xy+y²
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Complete Question

The complete question is shown on the first uploaded image

Answer:

the null hypothesis is  H_o  :  \mu =  122

the alternative hypothesis is H_a  :  \mu \ne  122

The test statistics is  t =  - 1.761

The p-value is  p =  P(Z  <  t ) = 0.039119

so

    p  \ge 0.01

Step-by-step explanation:

From the question we are told that

   The population mean is  \mu  = 122

     The sample size is  n=  38

    The sample mean is  \= x  =  116 \ feet

     The standard deviation is \sigma  =  21

     

Generally the null hypothesis is  H_o  :  \mu =  122

                the alternative hypothesis is H_a  :  \mu \ne  122

Generally the test statistics is mathematically evaluated as

         t =  \frac { \= x - \mu }{\frac{ \sigma }{ \sqrt{n} } }

substituting values

         t =  \frac { 116 -  122 }{\frac{ 21 }{ \sqrt{ 38} } }

         t =  - 1.761

The p-value is mathematically represented as

      p =  P(Z  <  t )

From the z- table  

     p =  P(Z  <  t ) = 0.039119

So  

     p  \ge 0.01

 

         

     

           

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