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pantera1 [17]
3 years ago
9

How many minutes are there in three quarters of an hour explain your answer

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
8 0
60 minutes in an hour.

1/4 × 60 = 15

3 quarters of an hour is

3 × 15 = 45 minutes
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A squared+ b squared=????​
Degger [83]

Answer:

<h2>a × a + b × b</h2>

<u>Step-by-step explanation:</u>

= a² + b²

= a × a + b × b

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3 years ago
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Mrrafil [7]

Answer:

the second one

Step-by-step explanation:

8 0
2 years ago
Please help asap. it’s 2 am and idk how to do this
lesya692 [45]

This is an example of a piecewise defined function. It means that the function has not a unique formula to represent it, but it depends on "where" you want to compute it.

So, if you choose any input x, you have two alternative:

  • If x \neq 3 (i.e., if you've chosen any input that is not 3), the output will be the opposite of the input you've chosen (y=-x)
  • If x=3, the ouput will be -1.

So, let's forget about x=3 for a moment. For any input x you choose, the answer is -x. The graph of this function is the bisector of the second and fourth quadrant.

Now remember that there is our special case: you have to "carve a hole" in our line, at x=3, and assing to this point the value -1, instead of what we would expect, i.e. -3.

So, the graph of this function is the line y=-x, except for one point (x=3), where we reassign the value to be -1.

5 0
3 years ago
The exponential function f(x) = 3(5)x grows by a factor of 25 between x = 1 and x = 3. What factor does it grow by between x = 5
Delvig [45]

Answer:

B) 25

Step-by-step explanation:

Given exponential function:

f(x)=3(5)^x

The growth factor between x=1 and x=3 is 25.

To find the growth factor between x=5 and x=7

Solution:

The growth factor of an exponential function in the interval x=a and x=b is given by :

G=\frac{f(b)}{f(a)}

We can check this by plugging in the given points.

The growth factor between x=1 and x=3 would be calculated as:

G=\frac{f(3)}{f(1)}

f(3)=3(5)^3

f(1)=3(5)^1

Plugging in values.

G=\frac{3(5)^3}{3(5)^1}

G=\frac{(5)^3}{(5)^1} (On canceling the common terms)

G=(5)^{(3-1)}  (Using quotient property of exponents \frac{a^b}{a^c}=a^{(b-c)} )

G=(5)^{2}

∴ G=25  

Similarly the growth factor between x=5 and x=7 would be:

G=\frac{f(7)}{f(5)}

f(7)=3(5)^7

f(5)=3(5)^5

Plugging in values.

G=\frac{3(5)^7}{3(5)^5}

G=\frac{(5)^7}{(5)^5} (On canceling the common terms)

G=(5)^{(7-5)}  (Using quotient property of exponents \frac{a^b}{a^c}=a^{(b-c)} )

G=(5)^{2}

∴ G=25  

Thus, the growth factor remains the same which is  =25.

3 0
3 years ago
Read 2 more answers
Please help me ASAP I NEED A ANSWER FAST
goldfiish [28.3K]
      drowning - kodak black 
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3 years ago
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