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kkurt [141]
3 years ago
7

Which set of numbers is INFINITE?

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
7 0
Im pe\retty sure its D because they can be multiplied byt he sam enumber many tines

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Four consecutive odd integers can be represented by n, n+2, n+4, and n+6. If the sum of the 4 consecutive odd integer is 46, wha
fgiga [73]
46 = n + n + 2 + n + 4 + n + 6
46 = 4n + 12

34 = 4n

n = 8.5

Is it definitely 46?
4 0
3 years ago
.
denpristay [2]

Answer:

x = 10, y = 0

Step-by-step explanation:

x + y = 10 ---> x = 10 - y

3x + 2y = 30

3 (10 - y) + 2y = 30

30 - 3y + 2y = 30

y = 0

x + 0 = 10

x = 10

3 0
3 years ago
Combine similar terms and apply the operation. Do NOT evaluate or simplify.
Airida [17]
1. 2x+ 4+3x
= (2x+ 3x)+ 4

2. <span>12 + 5x -8
= 5x + (12-8)

3. </span><span>2x^2 + 3x^2 + 4x
= (2x^2+ 3x^2)+ 4x

4. </span><span>5ax - 12 - ax
= (5ax -ax) -12

5. </span><span>4xy + 2x + 3xy + x
= (4xy+ 3xy)+ (2x+ x)

Hope this helps~</span>
7 0
3 years ago
A phycologist is interested in determining the proportion of algae samples from a local rivulet that belong to a particular phyl
LuckyWell [14K]

Answer:

A sample of 16577 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

99% confidence level

So \alpha = 0.01, z is the value of Z that has a p-value of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

She wants to estimate the proportion using a 99% confidence interval with a margin of error of at most 0.01. How large a sample size would be required?

We have no estimation for the proportion, and thus we use \pi = 0.5, which is when the largest sample size will be needed.

The sample size is n for which M = 0.01. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.01 = 2.575\sqrt{\frac{0.5*0.5}{n}}

0.01\sqrt{n} = 2.575*0.5

\sqrt{n} = \frac{2.575*0.5}{0.01}

(\sqrt{n})^2 = (\frac{2.575*0.5}{0.01})^2

n = 16576.6

Rounding up:

A sample of 16577 is required.

8 0
3 years ago
I need help solving this equation -3=9/(5-2k)/5
Amanda [17]

Solve for k by simplifying both sides of the equation, then isolating the variable.

k= 14/5



3 0
3 years ago
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