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jonny [76]
3 years ago
9

What is the molar mass of the unknown gas?

Chemistry
1 answer:
vovangra [49]3 years ago
4 0

First the ideal gas law will be used to solve for the moles of unknown gas (n). Then the mass of the gas divided by the moles will give the molar mass. Step 2: Solve. Now divide g by mol to get the molar mass.

Hope that helps!!!

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How many moles of CoH12O6 are consumed<br> if 6 moles of O2 are consumed?
Rashid [163]

Answer:

2

Explanation:

There are 3 moles O2 in 1 mole CoH12O6 so 2 moles are consumed

7 0
3 years ago
Why did me need to have the same molecules in each bottle? and what would have happened if we didn't use the same molecules?
NNADVOKAT [17]

Answer:

it's just like doing a test grade on children if you give them different tests they might not come up with the same results, the molecules need to be the same or else the experiment will be even.

Explanation:

whenever water is hot the molecules will bounce really fast in the bottle, whenever water is cold he will go really slow in the bottle

8 0
3 years ago
a helium filled balloon has a volume of 208 l and it contains 9.95 moles of gas. if the pressure of the balloon is 1.26 atm dete
daser333 [38]
To determine the temperature of the gas, we need to assume ideal gas to use the equation PV=nRT where P represents the pressure, V is the volume, n is the number of moles, T is the temperature and R is the universal gas constant. We calculate as follows:

PV = nRT
T = PV / nR

T = (1.26 atm) ( 208 L ) / 0.08205 L-atm/mol-K ( 9.95 mol )
T = 321.02 K

Hope this answers the question.
8 0
3 years ago
Answer fast please <br> Which is a tissue?
lina2011 [118]

Answer:

the last picture on the right (kinda red-ish)

Explanation:

First picture: organ

Second picture: system

Third picture: organism

Last picture: tissue

Hope this helps!

6 0
3 years ago
Read 2 more answers
PLS HELP ME I HAVE TILL 12
MariettaO [177]

Answer:

alright bud lets see hmm.... the answer is a. 90.5kpa

Explanation:

92.3 kPa - 1.82 kPa = 90.5 kPa

keep up your hope also corrected me if a am wrong in anyway! :)

3 0
3 years ago
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