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Andrej [43]
3 years ago
11

The energy absorbed or released when a neutral atom loses one electron

Chemistry
2 answers:
seropon [69]3 years ago
8 0

Answer: ionization energy

Explanation:

Ionization energy is the energy required to remove the most loosely bound electron from a gaseous atom.

M(g)\rightarrow M^++ne^{-1}

Metals have low ionization energy as they tend to attain stable configuration by losing the valence electrons. Example: Sodium

Nobles gases have high ionization energy as they do not tend to lose electrons easily due to their high stability.

In a group, the ionization energy decreases as we move down as the size increases and thus the valence shell moves farther from nucleus and thus is easier to remove.

In a period, the ionization energy increases as we move across, the size decreases and thus the valence shell moves near to the nucleus and thus it gets difficult to remove.

makvit [3.9K]3 years ago
7 0
It is called an ion.
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A drug is supplied as a 40 mg/ml solution in a 50 ml vial. you need to make 10 ml of a 10 mg/ml solution. how much concentrate w
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Answer: -

2.5 mL

Explanation: -

Volume of final solution = 10 mL

Strength of final solution = 10 mg / mL

Amount of drug required = Volume of final solution x strength of final solution

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Strength of supplied drug = 40mg/ mL

Volume of supplied drug required = \frac{100 mg}{40 mg/ mL}

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Is material that has a density of 0.2g/ml good for building a bridge or for making couch cushions
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8 0
4 years ago
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19 grams of sodium and 34 grams of chlorine are measured out and put into separate glass vials that weigh 10 grams each. Then so
vaieri [72.5K]

Answer:

63.02 g.

Explanation:

  • Na reacts with Cl₂ according to the balanced equation:

<em>2Na + Cl₂ → 2NaCl,</em>

It is clear that 2 mole of Na react with 1 mole of Cl₂ to  produce 2 moles of NaCl.

  • Firstly, we need to calculate the no. of moles of Na and Cl₂:

no. of moles of Na = (mass/atomic mass) = (19.0 g/22.9897 g/mol) = 0.826 g.

no. of moles of Cl₂ = (mass/atomic mass) = (34.0 g/70.906 g/mol) = 0.48 g.

  • From the stichiometry, Na reacts with Cl₂ with a molar ratio (2:1).

<em>So, 0.826 mol of Na "the limiting reactant" reacts completely with 0.413 mol of Cl₂ "left over reactant".</em>

The no. of moles of Cl₂ remained after the reaction = 0.48 mol - 0.413 mol = 0.067 mol.

∴ The mass of Cl₂ remained after the reaction = (no. of moles of Cl₂ remained after the reaction)(molar mass of Cl₂) = (0.067 mol)(70.906 g/mol) = 4.75 g.

  • To get the no. of grams of produced NaCl:

<u><em>using cross multiplication:</em></u>

2 mol of Na produce  → 2 mol of NaCl, from the stichiometry.

∴ 0.826 mol of Na produce  → 0.826 mol of NaCl.

∴ The mass of NaCl produced after the reaction = (no. of moles of NaCl)(molar mass of NaCl) = (0.826 mol)(58.44 g/mol) = 48.27 g.

∴ The total weight of the glass vial containing the final product = the weight of the glass vial + the weight of the remaining Cl₂ + the weight of the produced NaCl = 10.0 g + 4.75 g + 48.27 g = 63.02 g.

7 0
3 years ago
Read 2 more answers
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