All categories

3 years ago

Explain Newton’s third law of motion.

Chemistry

1 answer:

laiz [17]3 years ago

5 0

Answer:

His third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A. Notice that the forces are exerted on different objects.

Explanation:

You might be interested in

An atom has 19 protons and 20 neutrons. what is the atomic number with steps

sergey [27]

Answer:

Explanation:

add em up

4 0

3 years ago

Read 2 more answers

How does electronegativity impact polarity of molecules?

marysya [2.9K]

Electronegativity is the measure of the ability of an atom to attract electrons to itself. Fluorine is the most electronegative element and francium is one of the leastelectronegative. ... The molecule's polarity will be determined on the negative and positive regions on the outer atoms in the molecule.

6 0

3 years ago

Gold is currently trading at very high price. Suppose that gold is selling for around $1860/ounce. How

Ugo [173]

Answer:

The answer is "3.81041978"

Explanation:

$\to 1 \ OZ= 28.349523125 \ grams\\\\$

$=28.349523125\times {1000} \ miligrams\\\\= 28349. 5231 \ miligrams\\$

In 1860 $= 28349.5231 \ miligrams\\$

$\to In \$ \ 1 = \frac{28349.5231}{1860} \ \ miligrams\\$

$= 15.2416791 \ miligrams$

$\ In \ 1 \ quarter = \$ \ 0.25$

$\to \$ \ 0.25 = 15.2416791 \times 0.25 \ miligrams\\$

$= 3.81041978$

3 0

3 years ago

Calculate δg o for each reaction using δg of values:(a) h2(g) + i2(s) → 2hi(g) kj (b) mno2(s) + 2co(g) → mn(s) + 2co2(g) kj (c)

steposvetlana [31]

Part (a) :
H₂(g) + I₂(s) → 2 HI(g)
From given table:
G HI = + 1.3 kJ/mol
G H₂ = 0
G I₂ = 0
ΔG = G(products) - G(reactants) = 2 (1.3) = 2.6 kJ/mol

Part (b):
MnO₂(s) + 2 CO(g) → Mn(s) + 2 CO₂(g)
G MnO₂ = - 465.2
G CO = -137.16
G CO₂ = - 394.39
G Mn = 0
ΔG = G(products) - G(reactants) = (1(0) + 2*-394.39) - (-465.2 + 2*-137.16) = - 49.3 kJ/mol

Part (c):
NH₄Cl(s) → NH₃(g) + HCl(g)
ΔG = ΔH - T ΔS
ΔG = (H(products) - H(reactants)) - 298 * (S(products) - S(reactants))
= (-92.31 - 45.94) - (-314.4) - (298 k) * (192.3 + 186.8 - 94.6) J/K
= 176.15 kJ - 84.78 kJ = 91.38 kJ

6 0

3 years ago

Read 2 more answers

What is the percent by mass of carbon in acetone, c 3 h 6 o?

Tatiana [17]

In the problem, we are tasked to solved for the amount of carbon (C) in the acetone having a molecular formula of C 3 H 6 O. We need to find first the molecular weight if Carbon (C), Hydrogen (H), Oxygen (O).

Molecular Weight:
C=12 g/mol
H=1 g/mol
O=16 g/mol

To calculate for the percent by mass of acetone, we assume 1 mol of acetone.
%C= $( \frac{3(12 g/mol)}{3(12 g/mol)+6(1 g/mol)+16 g/mol} ) x 100%$
%C=62.07%
Therefore, the percent by mass of carbon in acetone is 62.07%

5 0

3 years ago

Read 2 more answers