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zzz [600]
3 years ago
10

A study was designed to compare the attitudes of two groups of nursing students towards computers. Group 1 had previously taken

a statistical methods course that involved significant computer interaction. Group 2 had taken a statistic methods course that did not use computers. The students' attitudes were measured by administering the Computer Anxiety Rating Scale (CARS). A random sample of 10 nursing students from Group 1 resulted in a mean score of 60.7 with a standard deviation of 6.9. A random sample of 15 nursing students from Group 2 resulted in a mean score of 66.3 with a standard deviation of 5.8. Can you conclude that the mean score for Group 1 is significantly lower than the mean score for Group 2? Let μ1 represent the mean score for Group 1 and μ2 represent the mean score for Group 2. Use a significance level of α=0.1 for the test. Assume that the population variances are equal and that the two populations are normally distributed. Step 1 of 4 : State the null and alternative hypotheses for the test.
Mathematics
1 answer:
NeX [460]3 years ago
3 0

Answer:

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A, B, and C are collinear, and B is between A and C. The ratio of AB to AC is 1:2 If A is at (6,3) and B is at (-1,2), what are
Maksim231197 [3]

Answer:

The coordinates of C is (-8,1)

Step-by-step explanation:

Looking at the attached image, you'd see that, AB is 1 and BC is 1, that's because we are told that ratio of AB to AC is 1:2 meaning, AC is 2 and AB is 1. Therefore for that ratio to be satisfied BC has to be 1 so that AC would be 2.

Now let's assume the coordinates of C is (x,y).

To get it's coordinates, we use the section formula:

(x,y)= (\frac{mx + nx_{1}}{m + n} , \frac{my + ny_{1}}{m + n})

Where (m,n) is the (AB, BC)

Therefore we have

(-1,2) = (\frac{1\times x + 1\times6}{1 + 1} , \frac{1\times y + 1\times3}{1 + 1})

This gives:

(-1,2) = (\frac{x + 6}{2} , \frac{y + 3}{2})

-1 =( \frac{x + 6}{2} and 2 = \frac{y + 3}{2})

From there x = -8 and y = 1

Therefore the coordinates of C is (-8, 1).

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