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zzz [600]
3 years ago
10

A study was designed to compare the attitudes of two groups of nursing students towards computers. Group 1 had previously taken

a statistical methods course that involved significant computer interaction. Group 2 had taken a statistic methods course that did not use computers. The students' attitudes were measured by administering the Computer Anxiety Rating Scale (CARS). A random sample of 10 nursing students from Group 1 resulted in a mean score of 60.7 with a standard deviation of 6.9. A random sample of 15 nursing students from Group 2 resulted in a mean score of 66.3 with a standard deviation of 5.8. Can you conclude that the mean score for Group 1 is significantly lower than the mean score for Group 2? Let μ1 represent the mean score for Group 1 and μ2 represent the mean score for Group 2. Use a significance level of α=0.1 for the test. Assume that the population variances are equal and that the two populations are normally distributed. Step 1 of 4 : State the null and alternative hypotheses for the test.
Mathematics
1 answer:
NeX [460]3 years ago
3 0

Answer:

wowrjdndndnfnf dmdi fufu diff fjf fjf fifth f ouch r f ik r fir fir rir tir t

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Solve 3[-x + (2 x + 1)] = x - 1.<br> x = 2
Gekata [30.6K]

Answer:

x = -2

Step-by-step explanation:

3[- x + (2x + 1)] = x - 1

=  > 3[ - x + 2x + 1 ] = x - 1

=  > 3[x + 1] = x - 1

=  > 3x + 3 = x - 1

=  > 3x - x =  - 1 - 3

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=  > x =  \frac{ - 4}{2}  =  - 2

7 0
3 years ago
Write an equation of the line, in standard form, containing the points (−6, 19) and (−15, 28).
Rudiy27

The equation of the line that contains (−6, 19) and (−15, 28), in standard form, is: x + y = 13

<em><u>Recall:</u></em>

  • Equation of a line can be written in standard from as Ax + By = C, where Ax and By are all terms of variable x and y, and C is a constant.
  • The equation of a line in point-slope, y - y_1 = m(x - x_1), can be rewritten in the standard form.
  • Slope (m) = \frac{y_2 - y_1}{x_2 - x_1}

Given: (−6, 19) and (−15, 28)

<em>Find the </em><em>slope </em><em>(m):</em>

<em />m = \frac{28 - 19}{-15 -(-6)} = \frac{9}{-9} = -1

Write the equation in point-slope form by substituting m = -1 and (x_1, y_1) = (-6, 19) into y - y_1 = m(x - x_1).

y - 19 = -1(x - (-6))\\\\y - 19 = -1(x + 6)

  • Rewrite in standard form

y - 19 = -1(x + 6)\\\\y - 19 = -x - 6\\\\y = -x - 6 + 19\\\\y = -x + 13\\\\\mathbf{x + y = 13}

Therefore, the equation of the line that contains (−6, 19) and (−15, 28), in standard form, is: x + y = 13

Learn more about equation of a line in standard form on:

brainly.com/question/19169731

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Brianna visits 20 houses every day in her
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Answer:

6 days

Step-by-step explanation:

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Geometry help??????
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Check the picture below.

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