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Allushta [10]
3 years ago
6

Consider the functions g(x) = 6x + 7 and h(x) = 3x - 2. find {x: g(x) > h(x)}

Mathematics
2 answers:
qaws [65]3 years ago
7 0
(-3, infinity). ik because i did this
makkiz [27]3 years ago
3 0

<u>Answer:</u>

The solution set is x ∈ ( -3 , ∞ ) .

<u>Step-by-step explanation:</u>

Two functions are given to us. And we have to find x such that g(x) > h(x) that is { x : g(x) > h(x)} .

So , the given functions are ,

  • g(x) = 6x + 7
  • h(x) = 3x - 2.

According to Question ,

⇒ g(x) > h(x)

⇒ 6x + 7 > 3x - 2

⇒ 6x - 3x > -2 -7

⇒ 3x > -9

⇒ x > (-9)/3

⇒ x > (-3)

Hence x can have all values greater than (-3). Therefore x ∈ (-3 , ∞ ) .

<h3><u>Hence </u><u>the </u><u>s</u><u>olution</u><u> set</u><u> </u><u>of</u><u> </u><u>x</u><u> </u><u>is</u><u> </u><u>x</u><u> </u><u>∈</u><u> </u><u>(</u><u>-</u><u>3</u><u>,</u><u>∞</u><u>)</u></h3>

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If 4x - 6≠4, then 2x–5≠5 is the contrapositive of a conditional statement if 2x -5=5, then 4x-6=14.

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