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Trava [24]
3 years ago
12

The sum of three consecutive numbers is 276. What is the smallest of these intengers?

Mathematics
1 answer:
shtirl [24]3 years ago
5 0

Answer:

91

Step-by-step explanation:

Let x be the smallest one:

● x is the first number

● x+1 is the second number

● x+2 is the third number

The sum of these numbers is 276

● x+(x+1)+(x+2) =276

● x+x+1+x+2 = 276

● 3x + 3 = 276

Substract 3 from both sides:

● 3x+3-3 = 276-3

● 3x = 273

Divide both sides by 3

● (3x)/3 = 273/3

● x = 91

So the smallest one is 91

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state whether the following statement is true or false: y= -x2 + 6x - 10 does not intersect the x-axis.​
oee [108]

Answer:

True

Step-by-step explanation:

Here, we want to check if the given equation does not intersect the x-axis

if it does not, then it has no real root

If the discriminant is less than zero, then it has no real roots and does not intersect the x-axis

The formula for the discriminant is;

D = b^2-4ac

In the question;

a = -1 , b = 6 , c = 10

so;

D = 6^2-4(-1)(10)

D = 36-40

D = -4

Since discriminant is less than zero, then there is no real root and the graph does not cross the x-axis

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3 years ago
You go to the post office to mail 6 letters. The postage for each letter is 39¢. How much money will the post office charge you
Alborosie
The answer is $2.34 hope this helps

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3 years ago
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Expand and simplify 9 (x-y)^2-9(x+y)(x-y)
yuradex [85]

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5 0
3 years ago
PLS HELP. Find the first four terms of the recursive sequence defined by the following formula:
Gnoma [55]

Answer:

see explanation

Step-by-step explanation:

Given the recursive formula a_{n} = \frac{a_{n-1} }{4} and

a_{4} = 2 \frac{1}{4} = \frac{9}{4}, then

\frac{a_{3} }{4} = \frac{9}{4} ( multiply both sides by 4 )

a₃ = 4 × \frac{9}{4} = 9

\frac{a_{2} }{4} = 9 ( multiply both sides by 4 )

a₂ = 36

\frac{a_{1} }{4} = 36 ( multiply both sides by 4 )

a₁ = 144

The first 4 terms are

144, 36, 9, 2 \frac{1}{4}

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3 years ago
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Molly ate 1/4 and then the last one is 1/8
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