complette the square to get vertex form or y=a(x-h)^2+k (h,k) is vertex 1. group x terms, so for y=ax^2+bx+c, do y=(ax^2+bx)+c
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2, factor out the leading coefinet (constant in front of the x^2 term), basicallly factor out a
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3. take 1/2 of the linear coefient (number in
front of the x), and square it ,then add negative and positive of it
inside parnthases
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4. complete the squre and expand
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so y=-1/4x^2+4x-19 group y=(-1/4x^2+4x)-19 undistribute -1/4 y=-1/4(x^2-16x)-19 take 1/2 of -16 and squer it to get 64 then add neg and pos inside y=-1/4(x^2-16x+64-64)-19 factorperfect square y=-1/4((x-8)^2-64)-19 expand y=-1/4(x-8)^2+16-19 y=-1/4(x-8)^2-3 vertex is (8,-3)
When parallel lines are cut by a transversal, then alternate interior angles are congruent. Angles PXY and XYS are alternate interior angles. m∠XYS = m∠PXY Answer: m∠XYS = 64.36°
