Answer:
210
Step-by-step explanation:
Here comes the problem from Combination.
We are being asked to find the number of ways out in which 3 students may sit on 7 seats in a row. Please see that in this case the even can not be repeated.
Let us start with the student one. For him all the 7 seats are available to sit. Hence number of ways for him to sit = 7
Let us see the student second. For him there are only 6 seats available to sit as one seat has already been occupied. Hence number of ways for him to sit = 6
Let us see the student third. For him there are only 5 seats available to sit as two seat has already been occupied. Hence number of ways for him to sit = 5
Hence the total number of ways for three students to be seated will be
7 x 6 x 5
=210
1-2m-5m=15
combine like terms
1 -7m = 15
subtract 1 from each side
1-1-7m = 15-1
simplify
-7m = 14
divide by -7
-7m/-7 = 14/-7
simplify
m = -2
For every 24 students there is one teacher. For every 12 students is one tutor. If the Academy had 132 students then you will need 11 tutors.
Answer:
x = 8
Step-by-step explanation:
4x + 3 = 35
subtract 3 from both sides
4x + 3 - 3 = 35 - 4
4x = 32
divide both sides by 4
4x / 4 = x
32/4 = 8
we're left with x = 8
Answer: it's B
step by step explanation: hope this helps
