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lilavasa [31]
3 years ago
8

the access code for a car's security system consists of four digits. the first digit cannot be 1 and the last digit must be even

or zero. how many different codes are available?
Mathematics
1 answer:
Stells [14]3 years ago
5 0
For the 1st digit we can use 9 of them ( it cannot be 1 ). For the 2nd and the 3rd we can use 10 and for last one we can use 5 digits ( 0, 2 , 4 , 6 and 8 ).
9 · 10 · 10 · 5 = 4,500
Answer: 4.500 different codes.
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Is 3/6 divided by 5 greater than 1?
Naily [24]

It is not greater than one.

When you divide 3/6 by 5, your quotient is 0.1, which has a value that is less than 1.

Hope this helps!

- sahira :>

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Find the area of the rectangle with the given base and height. 7 ft, 4 in
masha68 [24]

Answer:

336 sq. in or 2.333333333 sq. ft.

Step-by-step explanation:

1 foot = 12 in

7 x 12 = 84 in

A = bh

A = 84 in x 4 in

A = 336 sq. in

1 sq. ft. = 144 sq. in

336 / 144 = 2.33333333 sq. ft.

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XYZ are referred to as the area number. The number is associated with where you registered for your social security card. X is a
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9514 1404 393

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  700

Step-by-step explanation:

The numbers can range from 100 to 799. There are 700 possible numbers.

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Brynne has 13 books she has 8 more books than games how many game does Brynne have
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3 years ago
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A cash box contains $74 made up of quarters, half-dollars, and one-dollar
Strike441 [17]

Answer:

25 one-dollar coins, 16 half-dollar coins, and 164 quarters

Step-by-step explanation:

First, set up equations based on the information given:

0.25q+0.50h+1.00d=74

\displaystyle{h=\frac{3}{5}d+1}

q=4(d+h)

Then, substitute <em>q</em> in the first equation with the expression from the third equation:

0.25[4(d+h)]+0.50h+1.00d=74\\1d+1h+0.50h+1.00d=74\\2d+1.5h=74

Next, substitute <em>h</em> in that equation with the expression from the second equation:

\displaystyle{2d+1.5(\frac{3}{5}d+1)=74}

2d+0.9d+1.5=74\\2.9d+1.5=74

Solve for <em>d</em>, the number of one-dollar coins:

2.9d+1.5=74\\2.9d=72.5\\d=25

Substitute 25 for <em>d</em> in the second equation to find <em>h</em>, the number of half-dollar coins:

\displaystyle{h=\frac{3}{5}d+1}

\displaystyle{h=\frac{3}{5}(25)+1}

h=15+1\\h=16

Substitute 25 for <em>d</em> and 16 for <em>h</em> in the third equation to find <em>q</em>, the number of quarters:

q=4(d+h)\\q=4(25+16)\\q=4(41)\\q=164

Then, verify that the coins total $74:

0.25(164)+0.50(16)+1.00(25)=74\\41+8+25=74\\74=74\\\text{Check.}

Next, verify that the number of half-dollar coins is one more than three-fifths of the number of one-dollar coins:

\displaystyle{h=\frac{3}{5}d+1}

\displaystyle{16=\frac{3}{5}(25)+1}

16 = 15 + 1\\16 = 16\\\text{Check.}

Finally, verify that the number of quarters is four times the number one-dollar and half-dollar coins together:

q=4(d+h)\\164=4(25+16)\\164=4(41)\\164=164\\\text{Check.}

6 0
3 years ago
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