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lilavasa [31]
3 years ago
8

the access code for a car's security system consists of four digits. the first digit cannot be 1 and the last digit must be even

or zero. how many different codes are available?
Mathematics
1 answer:
Stells [14]3 years ago
5 0
For the 1st digit we can use 9 of them ( it cannot be 1 ). For the 2nd and the 3rd we can use 10 and for last one we can use 5 digits ( 0, 2 , 4 , 6 and 8 ).
9 · 10 · 10 · 5 = 4,500
Answer: 4.500 different codes.
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Nostrana [21]
3y = -2x + 2
y = x + 4 (Substitute the y)

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-2         - 2
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In the rolling of two fair dice calculate the following: P(Sum of the two dice is 7) = ______
vesna_86 [32]

Answer:

P(Sum of the two dice is 7) = 6/36

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem, we have that:

A fair dice can have any value between 1 and 6 with equal probability. There are two fair dices, so we have the following possible outcomes.

Possible outcomes

(first rolling, second rolling)

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)

(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)

(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)

(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)

(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)

(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

There are 36 possible outcomes.

Desired outcomes

Sum is 7, so

(1,6), (6,1), (5,2), (2,5), (3,4), (4,3).

There are 6 desired outcomes, that is, the number of outcomes in which the sum of the two dice is 7.

Answer

P(Sum of the two dice is 7) = 6/36

7 0
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