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mario62 [17]
3 years ago
11

The value of

gn="absmiddle" class="latex-formula"> where x is an integer, is located between 6 and 7 on the number line. What could be the value of x?
Mathematics
2 answers:
Alexandra [31]3 years ago
5 0

 

\displaystyle\\6

.

dimaraw [331]3 years ago
5 0

Answer:

Step-by-step explanation:

The value would be 6.5

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Find the equation of the line with slope m=1 that contains the point (7,5).
katovenus [111]

Answer:

y = x - 2

Step-by-step explanation:

y = mx + b

5 = 1 (7) + b

5 = 7 + b

b = -2

So...

y = x - 2

7 0
2 years ago
(5,2) (8,2), (8,5) and (?,?)
Luba_88 [7]
<h2>Answer:</h2><h2>(5,5)</h2><h2 /><h2>Hope this helps!!</h2><h2></h2>

6 0
3 years ago
Wendy is helping her mom put candy in 217 giftbagd. Each bag has 7 pieces of candy. She already put 58 pieces of candy in the ba
Ganezh [65]

Answer:

406 pieces. If you multiply 58 times 7 you get 406. 406 divided by 58 is 7.

4 0
3 years ago
The first three terms of a sequence are given. Round to the nearest thousandth (if necessary).
BabaBlast [244]

Step-by-step explanation:

the introduction of a fraction tells us that we are dealing with multiplications, and therefore a geometric sequence (where every new term is created by multiplying the previous term by a constant factor, the ratio r).

I think your teacher made a mistake, or you made one when typing the question in here.

there is no factor r that creates

15×r = 9

and

9×r = 5/27

it would mean that

15 × r² = 5/27

r² = 5/27 / 15 = 5/27 × 1/15 = 5/405 = 1/81

r = 1/9

but 15 × 1/9 = 5 × 1/3 = 5/3 is NOT 9

and 9 × 1/9 = 9/9 = 1 is NOT 5/27

so, this can't be right.

on the other hand

15 × r = 9

r = 9/15 = 3/5

and then

9 × 3/5 = 27/5

so, either the sequence should have been

15, 5/3, 5/27

or (and I suspect this to be true)

15, 9, 27/5

under that assumption we have

s1 = 15

r = 3/5

sn = sn-1 × r = s1 × r^(n-1) = 15 × (3/5)^(n-1)

s10 = 15 × (3/5)⁹ = 15 × 19683/1953125 =

= 3 × 19683/390625 = 59049/390625 =

= 0.15116544 ≈ 0.151

6 0
2 years ago
MATH HELP!!!!!<br><br> If y = 15 when x = 2, what is the value of x when y = 7?
Ede4ka [16]

<u>Direct Variation:</u>  \frac{y}{x} = k

\frac{15}{2} = k

when y = 7:      \frac{7}{x} = \frac{15}{2}

14 = 15x

\frac{14}{15} = x

<u>Inverse variation:</u>   y*x = k

15 * 2 = k

30 = k

when y = 7:      7 * x = 30

x = \frac{30}{7}


3 0
3 years ago
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