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Sever21 [200]
3 years ago
9

A material with a yield strength of 40 kpsi and an endurance strength of 20 kpsi is intended for an application with a von Mises

stress that alternates between 17 kpsi and 3 kpsi. What is the factor of safety, N, for the design?
Engineering
1 answer:
wlad13 [49]3 years ago
3 0

To solve this problem we will apply the concepts related to Soderberg's relation, which will allow us to find the safety factor based on yield stress, endurance strength, the mean and average stress. The mean and average stress values can be found through the alternating Stress previously given. We will proceed by defining the known values, that is

Yield stress \sigma_y = 40ksi

Endurance strength \sigma_e = 20ksi

The two values for alternating stress are

\sigma_1 = 17ksi

\sigma_2 = 3ksi

We know that mean stress is

\sigma_m = \frac{\sigma_1+\sigma_2}{2}

\sigma_m = \frac{17+3}{2} = 10ksi

And the average stress is

\sigma_v = \frac{\sigma_1-\sigma_2}{2}

\sigma_v = \frac{17-3}{2} = 7ksi

According to Soderberg relation

\frac{1}{F.s} = \frac{\sigma_m}{\sigma_y}+\frac{\sigma_v}{\sigma_e}

\frac{1}{F.s} = \frac{10}{40}+\frac{7}{20}

\frac{1}{F.s} = 0.6

F.s = 1.66 \approx 2

Therefore the factor of safety is 2

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Air is contained in a vertical piston–cylinder assembly such that the piston is in static equilibrium. The atmosphere exerts a p
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