Answer:
function summedValue = SummationWithLoop(userNum)
% Summation of all values from 1 to userNum
summedValue = 0;
i = 0;
% use a while loop that assigns summedValue with the
% sum of all values from 1 to userNum
while(i <= userNum)
summedValue = summedValue + i;
i = i + 1;
end
end
Answer:
Para x=0:
Para x=30 cm:
Explanation
Podemos utilizar la ley de Fourier par determinar el flujo de calor:
(1)
Por lo tanto debemos encontrar la derivada de T(x) con respecto a x primero.
Usando la ley de potencia para la derivda, tenemos:

Remplezando esta derivada en (1):
Para x=0:

Para x=30 cm:

Espero que te haya ayudado!
Answer:
// The method is defined with a void return type
// It takes a parameter of integer called numCycles
// It is declared static so that it can be called from a static method
public static void printShampooInstructions(int numCycles){
// if numCycles is less than 1, it display "Too few"
if (numCycles < 1){
System.out.println("Too few.");
}
// else if numCycles is less than 1, it display "Too many"
else if (numCycles > 4){
System.out.println("Too many.");
}
// else it uses for loop to print the number of times to display
// Lather and rinse
else {
for(int i = 1; i <= numCycles; i++){
System.out.println(i + ": Lather and rinse.");
}
System.out.println("Done");
}
}
Explanation:
The code snippet is written in Java. The method is declared static so that it can be called from another static method. It has a return type of void. It takes an integer as parameter.
It display "Too few" if the passed integer is less than 1. Or it display "Too much" if the passed integer is more than 4. Else it uses for loop to display "Lather and rinse" based on the passed integer.
Answer:
hello your question is incomplete attached below is the complete question
A) overall mean = 5.535, standard deviation ≈ 0.3239
B ) upper limit = 5.85, lower limit = 5.0
C) Not all the samples meet the contract specifications
D) fluctuation ( unstable Asphalt content )
Explanation:
B) The daily average asphalt content has to obtained in order to determine the upper and lower control limits using an average asphalt content of 5.5% +/- 0.5% everyday
The upper limit : 14 may = ( 5.8 + 5.1 ) / 2 = 5.85
The lower limit : 16 may = ( 5.2 + 4.8 ) / 2 = 5.0
attached below is the required plot
C ) Not all the samples meet the contract specifications and the samples that do not meet up are samples from :
15 may and 16 may . this is because their Asphalt contents are 6.2 and 4.8 respectively and sample number 18 and 20
D ) what can be observed is that the ASPHALT content fluctuates between the dates while the contract specification is fixed