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Gwar [14]
3 years ago
6

For each topic, find the total number of blurts that were analyzed as being related to the topic. Order the result by topic id.

Your SQL query should print the topic id, topic description and the corresponding count.user (email, password, name, date_of _birth, address, type) primary keyſemail) celebrity (email, website, kind) primary keyemail) blurt (blurtid, email, textlocation, time) primary keyblurtid,email ) foreign key (email) references user(email) hobby (email, hobby) primary keyſ emailhobb, ) foreign key(email) references user(email) . follow (follower, followee) primary key(follower.followee) foreign key follower) references user(email) foreign keyfollowee) references user(email) vendor (id, name rimary keyid) vendorambassador (vendorid. email) primary keyſvendorid) foreign key(email) references userſ email) foreign keyvendorid) references vendor(id) topic (id, description) primary keyſid) vendor_topics (vendorid, topicid) primary keyvendorid, topicid) foreign keyvendorid) references vendor(id) foreign keytopicid) references topic(id)

Engineering
1 answer:
photoshop1234 [79]3 years ago
8 0

Answer:

Explanation: see attachment below

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During the pre-drive check, you'll want to observe the car from the _______.
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Answer:

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Explanation:

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5 0
3 years ago
You have been assigned to design an open cylindrical storage tank 4 meters tall with a diameter of 8 meters to be made out of A-
Katen [24]

Answer:

The required wall thickness is 1.506 \times 10^{-3} m

Explanation:

Given:

Fluid density \rho = 1200 \frac{kg}{m^{3} }

Diameter of tank d = 8 m

Length of tank l = 4 m

F.S = 4

For A-36 steel yield stress \sigma = 250 MPa,

Allowable stress \sigma _{allow} = \frac{\sigma}{F.S}

 \sigma _{allow} = \frac{250}{4} = 62.5 MPa

Pressure force is given by,

 P = \rho gh

 P = 1200 \times 9.8 \times 4

P = 47088 Pa

Now for a vertical pipe,

\sigma _{allow} = \frac{Pd}{4t}

Where t = required thickness

 t = \frac{Pd}{4 \sigma _{allow} }

 t = \frac{47088 \times 8 }{4 \times 62.5 \times 10^{6} }

t = 1.506 \times 10^{-3} m

Therefore, the required wall thickness is 1.506 \times 10^{-3} m

8 0
3 years ago
A Si sample contains 1016 cm-3 In acceptor atoms and a certain number of shallow donors, the In acceptor level is 0.16 eV above
creativ13 [48]

Answer:

6.5 × 10¹⁵/ cm³

Explanation:

Thinking process:

The relation N_{o} = N_{i} * \frac{E_{f}-E_{i}  }{KT}

With the expression Ef - Ei = 0.36 × 1.6 × 10⁻¹⁹

and ni = 1.5 × 10¹⁰

Temperature, T = 300 K

K = 1.38 × 10⁻²³

This generates N₀ = 1.654 × 10¹⁶ per cube

Now, there are 10¹⁶ per cubic centimeter

Hence, N_{d}  = 1.65*10^{16}  - 10^{16} \\           = 6.5 * 10^{15} per cm cube

5 0
2 years ago
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Answer:

the answer is d 83.3%

Explanation:

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