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Brilliant_brown [7]
2 years ago
13

Read the word problem. Hershel buys 5 bags of cookies, 3 bags of granola, and several bags of fruit snacks from a bake sale. In

total, he buys 10 bags from the bake sale. How many bags of fruit snacks did Hershel buy? Which type of word problem is shown? part-whole comparison multiplication division
Mathematics
1 answer:
agasfer [191]2 years ago
5 0

Answer : Hershel buys 2 bags of fruit snacks.

Explanation :

Since we have given that

Number of bags of granola =3

Number of bags of cookies = 5

Total number of bags he buys from the bake sale =10

\text{Remaining bags are of fruit snacks} =10-(5+3)=10-8=2

So, number of bags of fruit snacks = 2

Hence, Hershel buys 2 bags of fruit snacks .

It is a comparison type of word problem.  

As we just compare the items with the total items to get the remaining items.

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The ratio of Val's savings to Dan is 2:3 at first. After Dan spent P3000.00, Val's saving became 11/3 more of that Dan's remaini
andrew11 [14]

Answer:

P.7500.00

Step-by-step explanation:

We are told that:

The ratio of Val's savings to Dan is 2:3 at first.

Now, Dan spent P3000.00 and Val's saving became 1⅓ more of that Dan's remaining savings.

Let's say the total amount of savings they had at first was x.

Thus;

Val had: 2x/5

Dan had: 3x/5

Now, Dan spent P3000.00.

So amount Dan has left = (3x/5) - 3000

We are told Val's savings is now 1⅓ = 4/3 times that of Dan's remaining savings

Thus; 2x/5 = (4/3)((3x/5) - 3000)

2x/5 = 12x/15 - 4000

Multiply through by 15 to get;

6x = 12x - (3000 × 15)

6x = 12x - 45000

Rearranging, we have;

12x - 6x = 45000

6x = 45000

x = 45000/6

x = P.7500

4 0
3 years ago
Which choice is equivalent to the expression below ? sqrt -12
STALIN [3.7K]
There’s no answer choices
6 0
3 years ago
Read 2 more answers
The Lacrosse booster club is holding a raffle for a fundraiser. They will sell 100 tickets for $5 each and select 4 winners. All
Nadusha1986 [10]

Answer:

<h2>There are 3,921,225 ways to select the winners.</h2>

Step-by-step explanation:

This problem is about combinations with no repetitions, because the same person can't win four times. It's a combinaction because the order of winning doesn't really matter.

Combinations without repetitions are defined as

C_{n}^{r}  =\frac{n!}{r!(n-r)!}

Where n=100 and r=4.

Replacing values, we have

C_{100}^{4}  =\frac{100!}{4!(100-4)!}=\frac{100!}{4! 96!}=\frac{100 \times 99 \times 98 \times 97 \times 96!}{4! \times 96!}=  \frac{94,109,400}{24}= 3,921,225

Therefore, there are 3,921,225 ways to select the winners.

Additionally, as you can imagine, the probability of winning is extremely low, it would be 3,921,225 to 1.

3 0
3 years ago
4. The sum of three consecutive odd integers is 36.
PilotLPTM [1.2K]

Answer:

11, 12, 13

Step-by-step explanation:

n, n + 1, n +2

The sum will add to 36

5 0
3 years ago
Please Help Me! I need to pass.
Andru [333]
42 is the answer

Explanation:
50% of 80 is half of 80 which is 40

Then you would add 40 with 5% of 40

What you would do then is 5% times 40 then you would change the 5% into a decimal which is 0.05 and multiply it by 40 , which would get u 2

Then you would add the price with tax
40+2 = 42
6 0
2 years ago
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