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forsale [732]
3 years ago
12

Lori is drawing a picture of her dining room. The scale in her drawing is 3in : 6ft. The length of the living room is 8 inches a

nd the width is 15 inches. What are the length and width of the actual room? Find the area of the actual room.
Mathematics
1 answer:
zhenek [66]3 years ago
8 0

Answer:

480 ft

Step-by-step explanation:

1 ft = 12 in, so 3in : 6ft would be 3in : 72in, which can be simplified to 1in : 24in. then you use the scale to find the lengths. 8in: (24·8)in. 24 · 8 = 192. to convert to feet, do 192/12=16ft. for the width, do the same thing. 15in: (24·15)in. 24·15=360. 360/12=30ft. For area, multiply the length and width. 16·30=480ft.

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6x + 5y = 16<br> −6x + 7y = 80
Kobotan [32]

The equation of the line in point-slope form is equal to

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step 1

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step 2

convert to standard form

6 0
3 years ago
Daisy wants to find out where the greatest number of people buy fast food for lunch. He surveys every fourth person on a random
vekshin1

Answer:

B

Step-by-step explanation:

that way when surveying everyone she’ll know the exact number

6 0
3 years ago
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the sum of two numbers is 67 if three times the smaller number is subtracted by the larger the result is 7, find two numbers
just olya [345]
Um I think it's 3x7x4=81 or like this 40+20+7=67.
3 0
3 years ago
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A machine that produces ball bearings has initially been set so that the true average diameter of the bearings it produces is .5
lara [203]

Answer:

7.3% of the bearings produced will not be acceptable

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 0.499, \sigma = 0.002

Target value of .500 in. A bearing is acceptable if its diameter is within .004 in. of this target value.

So bearing larger than 0.504 in or smaller than 0.496 in are not acceptable.

Larger than 0.504

1 subtracted by the pvalue of Z when X = 0.504.

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.504 - 0.494}{0.002}

Z = 2.5

Z = 2.5 has a pvalue of 0.9938

1 - 0.9938= 0.0062

Smaller than 0.496

pvalue of Z when X = -1.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.496 - 0.494}{0.002}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.0668 + 0.0062 = 0.073

7.3% of the bearings produced will not be acceptable

4 0
3 years ago
5. Landon bought a new car for $16,000 and it depreciates 4.5% every year. Write a function that describes
snow_tiger [21]

Answer:

<h3>The value C(t) of the car after  5  years is $12709.</h3>

Step-by-step explanation:

Given that Landon bought a new car for $16,000 and it depreciates 4.5% every year.

<h3>To find the value C(t) of the car after  5  years:</h3>

Initial value C(0)= $16,000

Depreciation rate is  r=\frac{4.5}{100}

<h3>∴ r=0.045</h3>

Period ,  t=5 years

C(t)=C(0)(1-r)^t

Substitute the values we get

C(5)=16000(1-0.045)^5

=16000(0.955)^5

=16000(0.7943)

∴ C(5)=12708.8

<h3>The value C(t) of the car after  5  years is  $ 12709</h3>
3 0
3 years ago
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