In this case the two equations<span> describe lines that intersect at one particular point. Clearly this point is on both lines, and therefore its coordinates (x, y) will satisfy the </span>equation<span> of either line. Thus the pair (x, y) is the one and only </span>solution to the system of equations<span>.</span>
Answer:
y² = 9² + 19² - 2(9)(19)Cos (41°)
Step-by-step explanation:
Triangle X Y Z is shown.
The length of X Y is 9,
the length of Y Z is 19, and the length of X Z is y. Angle X Y Z is 41 degrees.
Law of cosines is given as:a²= b² + c² – 2bccos(A)
Applying this to Triangle XYZ, and since we are Solving for y
y² = x² + z² - 2xzCos Y
The length of X Y = x is 9,
the length of Y Z = y is 19
y²= 9² + 19² - 2(9 × 19)Cos (41°)
= y² = 9² + 19² - 2(9)(19)Cos (41°)
Option d is correct
6 - x/10 = -3
6 = -3 + x/10
9 = x/10
90 = x
Answer:
the answer is D
Step-by-step explanation:
on edge2020
