Solution:
we are given that
Inscribed angle
Intercepted arc
As we know that the Inscribed angle is Half of the measure of the intercepted arc.
So we can write
1/2 is the answer bc it is the best choice between them so
Answer:
y= -4x^2 + 15x - 14
Step-by-step explanation:
A parabola is always in the form y = ax^2 + bx + c.
Substitute each point to produce different equations:
-14 = 0a + 0b + c = c
so c = -14
-3 = a1^2 + b1 + c = a + b - 14
so a + b = 11
0 = a2^2 + b2 + c = 4a + 2b -14 = 0
so 4a + 2b = 14
if we double a + b = 11 we get 2a + 2b = 22
Subtract this from 4a + 2b = 14 and we get 2a = -8 so a= -4 and b = 11 - a = 15
We don't need to use the (3,5) points as we have all the information we need.
You can multiply by -30 to clear fractions.
.. 47 ≤ 10x +60
Now, subtract 60 and divide by 10
.. -13 ≤ 10x
.. -1.3 ≤ x
An 8th-degree polynomial needs 9 terms that involve
x⁸, x⁷, ..., x¹, and x⁰.
x=10 implies that (x-10) is a factor of the polynomial according to the Remainder theorem.
Let the polynomial be of the form
f(x) = a₁x⁸ + a₂x⁷ + a₃x⁶ +a₄x⁵ + a₅x⁴ + a₆x³ + a₇x² + a₈x + a₉
The first few lines of the synthetic division are
10 | a₁ a₂ a₃ a₄ a₅ a₆ a₇ a₈ a₉ ( the first row has 9 coefficients)
-----------------------------------------
a₁
Answer:
The first row has 9 coefficients.
