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uysha [10]
3 years ago
13

What is the mode and outlier for 116, 119, 121, 122, 124, 128?

Mathematics
2 answers:
topjm [15]3 years ago
7 0
They all would be the mode (the mode is the one that occurs the most and they all occur once) and the outlier would technically be 128 but it still isn't really an outlier.
Zarrin [17]3 years ago
3 0
The mode is the one that occurs most often so the answer would be all of them
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sertanlavr [38]

Answer:

33+12t−21t^2

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(2t-7)²-(5t-4)²

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4t^2−28t+49−(5t-4)²

Use binomial theorem (a−b)^2 = a^2−2ab+b^2 to expand (5t-4)².

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To find the opposite of 25t^2

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4t^2−28t+49−25t^2−40t+16

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−21t^2−28t+49+40t−16

Combine −28t and 40t to get 12t.

−21t^2+12t+49−16

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−21t^2+12t+33

Swap terms to the left side.

33+12t−21t^2

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5 0
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the table is multiplying by 5

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3 years ago
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