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Fiesta28 [93]
3 years ago
7

The product of two consecutive integers is 72. The equation x(x + 1) = 72 represents the situation, where x represents the small

er integer. Which equation can be factored and solved for the smaller integer?
Mathematics
2 answers:
Marta_Voda [28]3 years ago
8 0
For this case we have the following equation:
 x (x + 1) = 72

 We can rewrite the expression.
 For this, we first make distributive property:
 x ^ 2 + x = 72

 Then, we add -72 on both sides of the equation:
 x ^ 2 + x - 72 = 72 - 72

 Rewriting we have:
 x ^ 2 + x - 72 = 0

 This is the equation that must be factored and solved for the smallest integer.
 Answer:
 
An equation that can be factored and solved for the smaller integer is:
 
x ^ 2 + x - 72 = 0
DochEvi [55]3 years ago
6 0

Answer:

The smallest integer is 8

Step-by-step explanation:

x(x+1)=72

applying distributive law in Right hand side and subtracting 72 from both hand sides we get

x^2+x-72=0

Now we are required to find the factors of 72 , such that their difference is 1. The factors are 8 and 9 and 9-8=1. Hence they satisfies our requirements. Now we split the middle term like

x^2+9x-8x-72=0

taking x and 8 as GCF from brackets

x(x+9)-8(x+9)=0

(x-8)(x+9)=0

Hence  

if (x-8)=0 ; x=8

if  (x+9)=0 ; x=-9

Hence our answer is 8 and 9

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