Answer:
30.49 m
Step-by-step explanation:
To obtain the maximum height, we solve for the value x when dy/dx = 0.
Since, y = -5x² + 40x + 20
dy/dx = d[-5x² + 40x + 20]/dx
dy/dx = -10x + 40
Since dy/dx = 0,
-10x + 40 = 0
-10x = -40
x = -40/-10
x = 4
Substituting x = 4 into the equation for y, we have
y = -5x² + 40x + 20
y = -5(4)² + 40(4) + 20
y = -5(16) + 160 + 20
y = -80 + 160 + 20
y = 80 + 20
y = 100 ft
Since y is in feet, we convert to meters.
Since 1 m = 3.28 ft, 100 ft = 100 ft × 1 m/3.28 ft = 30.49 m
So, the maximum height, in meters reached by the projectile is 30.49 m
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12-3(10+23):9x(-2)
(I don’t understand the “:” but it is right next to the / sign, so I will solve like that)
Answer:
look at the picture i have sent
Step-by-step explanation:
The given equation is
As a check for exactness we have
Hence the given equation is an exact differential equation and thus the solution is given by
thus the solution is given by
Similarly we have
Comparing both the solutions we infer
Hence the solution becomes
given boundary condition is that it passes through (1,1) hence
thus solution is
