Answer:
10. (5, 6)
11. (1, 2)
12. (7, 8)
13. (10, 11)
14. (27, 28)
15. (11, 12)
Step-by-step explanation:
If you're not familiar with the squares of small integers, your calculator can help you figure this.
10. √28 ≈ 5.291 . . . . between 5 and 6
11. √3 ≈ 1.732 . . . . between 1 and 2
12. √59 ≈ 7.681 . . . . between 7 and 8
13. √115 ≈ 10.724 . . . between 10 and 11
14. √772 ≈ 27.785 . . . . between 27 and 28
15. √140 ≈ 11.832 . . . . between 11 and 12
(a) 4
(b) y = sqrt(9 - (9/16)x^2)
The best guess to the formula using knowledge of the general formula for an ellipse is:
x^2/16 + y^2/9 = 1
(a). An ellipse is reflectively symmetrical across both the major and minor axis. So if you can get the area of the ellipse in a quadrant, then multiplying that area by 4 would give the total area of the ellipse. So the factor of 4 is correct.
(b). The general equation for an ellipse is not suitable for a general function since it returns 2 y values for every x value. But if we restrict ourselves to just the positive value of a square root, that problem is easy to solve. So let's do so:
x^2/16 + y^2/9 = 1
x^2/16 + y^2/9 - 1 = 0
x^2/16 - 1 = - y^2/9
-(9/16)x^2 + 9 = y^2
9 - (9/16)x^2 = y^2
sqrt(9 - (9/16)x^2) = y
y = sqrt(9 - (9/16)x^2)
Answer:
3
Step-by-step explanation:
Answer:
B., C., and E or 2, 3, and 5
Step-by-step explanation:
I did it and got it right.
I cant see the picture good can you write it out not in picture because it is blury for me I dont know about the others
