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3 years ago

Solve using the quadratic frmula 2x^2-5x=3

Mathematics

2 answers:

Blizzard [7]3 years ago

5 0

Answer:

3 and -1/2

Step-by-step explanation:

The quadratic formula is $(- b +/- \ sqrt{b^2-4ac} )/2a$ , for ax^2+bx+c=0.

You're equation is 2x^2-5x=3. Subtract 3 on both sides to get 2x^2-5x-3=0. Now we plug this in into the quadratic formula to get $(5+/-\sqrt{25-(-24)} )/4$ which is equal to $(5+/- \sqrt{49} )/4 = (5+/- 7)/4.$ There are 2 solutions, one being (5+7)/4= 12/4= 3, and the other being (5-7)/4=-2/4=-1/2/

Mnenie [13.5K]3 years ago

4 0

2x2−5x=3

I think the first step would be to

Subtract 3 from both sides

2x2−5x−3=3−3

2x2−5x−3=0

Then

For this equation: a=2, b=-5, c=-3

2x2+−5x+−3=0

Lastly you would

Use quadratic formula with a=2, b=-5, c=-3

I think your answer would then have to be...

x = 3 or x = −1 /2

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Ann can swim 20 laps in 8 min. how long will it take to swim 9 laps? show your equations(s).

Volgvan

Take 20 laps divide by 8 then take the number times 9 laps

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3 years ago

Marty is asked to draw triangles with side lengths of 4 units and 2 units, and a non-included angle of 30°. Select all the trian

777dan777 [17]

Answer:

The drawn in the attached figure

see the explanation

Step-by-step explanation:

<em>First case</em>

In the triangle ABC

Let

$a=4\ units\\b=2/ units\\B=30^o$

Applying the law of sines

Find the measure of angle A

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{4}{sin(A)}=\frac{2}{sin(30^o)}$

$sin(A)=1$

$A=90^o$

Find the measure of angle C

In a right triangle

we know that

$B+C=90^o$ ----> by complementary angles

$B=30^o$

therefore

$C=60^o$

Find the length side c

Applying the law of sines

$\frac{c}{sin(C)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{c}{sin(60^o)}=\frac{2}{sin(30^o)}$

$c=2\sqrt{3}\ units$

therefore

The dimensions of the triangle are

$A=90^o$

$B=30^o$

$C=60^o$

$a=4\ units\\b=2\ units\\c=2\sqrt{3}=3.46\ units$

<em>Second case</em>

In the triangle ABC

Let

$a=4\ units\\b=2/ units\\A=30^o$

Applying the law of sines

Find the measure of angle B

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{4}{sin(30^o)}=\frac{2}{sin(B)}$

$sin(B)=0.25$

using a calculator

$B=14.48^o$

Find the measure of angle C

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

$A+B+C=180^o$

$A=30^o\\B=14.48^o$

therefore

$30^o+14.48^o+C=180^o$

$C=135.52^o$

Find the length side c

Applying the law of sines

$\frac{c}{sin(C)}=\frac{a}{sin(A)}$

substitute the given values

$\frac{c}{sin(135.52^o)}=\frac{4}{sin(30^o)}$

$c=5.61\ units$

therefore

The dimensions of the triangle are

$A=30^o$

$B=14.48^o$

$C=135.52^o$

$a=4\ units\\b=2\ units\\c=5.61\ units$

see the attached figure to better understand the problem

4 0

3 years ago

Find the slope and the equation please<br><br>and step by step PLEASE.

Svetllana [295]

Answer:

y = $\frac{-4}{5}$ x + 1

Step-by-step explanation:

Slope is rise over run, or the vertical progression over the horizontal progression.

Your example has a line that heads downwards, so we know that the slope is negative. If we count the squares, the "rise" is down by 4. We count the squares going horizontally and there are 5. So, your slope is $\frac{-4}{5}$ .

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2 years ago

In a continuous series, mean(x) = 80, assumed mean(A) = 60 and<br>EF=40 then find the value of EFd.

Aneli [31]

Using the given information, the value of Σfd is 800

<h3>Calculating mean using Assumed mean </h3>

From the question, we are to determine the value of Σfd

The formula for mean, using the assumed mean method is given by

$\bar x = A + \frac{\sum fd}{\sum f}$

Where $\bar x$ is the mean

A is the assumed mean

From the given information,

$\bar x = 80$

$A = 60$

$\sum f = 40$

Putting the parameters into the equation, we get

$80 = 60 + \frac{\sum fd}{40}$

$80-60 = \frac{\sum fd}{40}$

$20 = \frac{\sum fd}{40}$

$\sum fd = 20 \times 40$

$\sum fd = 800$

Hence, the value of Σfd is 800

Learn more on Mean here: brainly.com/question/20118982

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DENIUS [597]

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\\\\\\
\left( -\cfrac{3}{\sqrt{13}}~~,~~ \cfrac{2}{\sqrt{13}}\right)\\\\
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$\bf \textit{and now let's \underline{rationalize} the denominator for each}
\\\\\\
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\\\\\\
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3 years ago