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Ira Lisetskai [31]
3 years ago
7

Solve using the quadratic frmula 2x^2-5x=3

Mathematics
2 answers:
Blizzard [7]3 years ago
5 0

Answer:

3 and -1/2

Step-by-step explanation:

The quadratic formula is (- b +/- \ sqrt{b^2-4ac} )/2a, for ax^2+bx+c=0.

You're equation is 2x^2-5x=3. Subtract 3 on both sides to get 2x^2-5x-3=0. Now we plug this in into the quadratic formula to get (5+/-\sqrt{25-(-24)} )/4 which is equal to (5+/- \sqrt{49} )/4 = (5+/- 7)/4.There are 2 solutions, one being (5+7)/4= 12/4= 3, and the other being (5-7)/4=-2/4=-1/2/

Mnenie [13.5K]3 years ago
4 0

2x2−5x=3

I think the first step would be to

Subtract 3 from both sides

2x2−5x−3=3−3

2x2−5x−3=0

Then

For this equation: a=2, b=-5, c=-3

2x2+−5x+−3=0

Lastly you would

Use quadratic formula with a=2, b=-5, c=-3

I think your answer would then have to be...

x = 3 or x =  −1 /2

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Answer:

1245

Step-by-step explanation:

You have to multiply 415 and 3, since 10 x 3 = 30

415 x 3 = 1245

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KATRIN_1 [288]
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Answer:

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Step-by-step explanation:

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3 years ago
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user100 [1]

Answer:

9.5\times 10^{6}

Step-by-step explanation:

1. Divide the coefficients and the exponentials separately

\dfrac{3.8 \times 10^{9}}{4 \times 10^{2}} = \dfrac{3.8}{4} \times \dfrac{10^{9}}{10^{2}}

2. Divide the coefficients

\dfrac{3.8}{4} = 0.95

3. Divide the exponentials

Subtract the exponent in the denominator from the exponent in the numerator.

\dfrac{10^{9}}{10^{2}} = 10^{(9 - 2)} = 10 ^{7}

4. Re-join the new coefficient and the new exponential

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5. Put the new number into standard form

The number before the power of 10 must be greater than or equal to one and less than 10.

Multiply the answer by 10/10.

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