Question

Solve using the quadratic frmula 2x^2-5x=3

Answer 1

Answer:

3 and -1/2

Step-by-step explanation:

The quadratic formula is $(- b +/- \ sqrt{b^2-4ac} )/2a$, for ax^2+bx+c=0.

You're equation is 2x^2-5x=3. Subtract 3 on both sides to get 2x^2-5x-3=0. Now we plug this in into the quadratic formula to get $(5+/-\sqrt{25-(-24)} )/4$ which is equal to $(5+/- \sqrt{49} )/4 = (5+/- 7)/4.$There are 2 solutions, one being (5+7)/4= 12/4= 3, and the other being (5-7)/4=-2/4=-1/2/

Answer 2

2x2−5x=3

I think the first step would be to

Subtract 3 from both sides

2x2−5x−3=3−3

2x2−5x−3=0

Then

For this equation: a=2, b=-5, c=-3

2x2+−5x+−3=0

Lastly you would

Use quadratic formula with a=2, b=-5, c=-3

I think your answer would then have to be...

x = 3 or x =  −1 /2