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Rainbow [258]
3 years ago
15

Lorenas backpack has a mass of 10000 grams what is the mass of Lorenas backpack in kilograms

Mathematics
1 answer:
Travka [436]3 years ago
8 0
Lorenas backpack is has the mass of 10000 grams so in kilograms the mass of Lorenas backpack in kilograms would simply be 10 kilograms
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Use the information provided to determine a 95% confidence interval for the population variance. A researcher was interested in
Leno4ka [110]

Answer:

The 95% confidence interval for the population variance is (8.80, 32.45).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the population variance is given as follows:

\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}

It is provided that:

<em>n</em> = 20

<em>s</em> = 3.9

Confidence level = 95%

⇒ <em>α</em> = 0.05

Compute the critical values of Chi-square:

\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2, (20-1)}=\chi^{2}_{0.025,19}=32.852\\\\\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.05/2, (20-1)}=\chi^{2}_{0.975,19}=8.907

*Use a Chi-square table.

Compute the 95% confidence interval for the population variance as follows:

\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}

\frac{(20-1)\cdot (3.9)^{2}}{32.852}\leq \sigma^{2}\leq \frac{(20-1)\cdot (3.9)^{2}}{8.907}\\\\8.7967\leq \sigma^{2}\leq 32.4453\\\\8.80\leq \sigma^{2}\leq 32.45

Thus, the 95% confidence interval for the population variance is (8.80, 32.45).

4 0
3 years ago
(a) Calculate the angle of the following diagram.<br>Answer:​
Stolb23 [73]

Diagram please

Without diagram I cannot tell you the answer

3 0
3 years ago
Find the value of x if 196^×=14​
castortr0y [4]

Answer:

x = \frac{1}{2}

Step-by-step explanation:

Note that \sqrt{196} = 14

Expressed in exponent form as

196^{\frac{1}{2} } = 14, thus

x = \frac{1}{2}

7 0
3 years ago
Two automobiles start together from the same place and travel along the same route. The first averages 40 miles
natita [175]

Answer:

A. (55 x 5) - (40 x 5)

Step-by-step explanation:

You are solving how much miles (further along) would the second car be after 5 hours.

The first car averages 40 miles per hour. 5 hours later, it will have averaged about 200 miles in 5 hours (40 x 5 = 200).

The second car averages 55 miles per hour. 5 hours later, it will have averaged about 275 miles in 5 hours (55 x 5 = 275)

Subtract: 275 - 200 = 75

The second car would have averaged 75 more miles than the first car.

~

4 0
3 years ago
Read 2 more answers
What is the value of 8(15-4)/4^2-5
kolbaska11 [484]

Answer: 0.5


Step-by-step explanation:

Android calculator accepts the above question via copy and paste, and gives 0.5


The point of this question is to try to discover whether or not you know what the expression means.


Rewriting it as (8(15-4)/(4×4)) - 5 would show that you know the meaning. You can check that by feeding it into the calculator as well.

4 0
2 years ago
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