Answer:
ABC=BCD wtdf
Step-by-step explanation:
Represent these consecutive numbers (assuming that they are all integers):
x
x+1
x+2
x+3
x+4
x+5
and so on
x+8
x+9 is the tenth number. x+9 = 10, so x = 9.
Think of it this way: there are 10 consecutive numbers, and the last one is 10.
Working backwards, we get the sequence 10, 9, ... 3, 2, 1.
The sum of such an arith sequence is equal to the count of the numbers times the average of the first and last terms:
sum here = 10(1+10)/2 = 5(11) = 55 (answer)
6.
![y^2\sqrt[8]{8}](https://tex.z-dn.net/?f=y%5E2%5Csqrt%5B8%5D%7B8%7D)
Step-by-step explanation:
![\sqrt[8]{8*y*y*y*y*y*y*y*y*y*y*y*y*y*y*y*y}](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7B8%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%7D)
Since there are eight y's in two groups we can take them out which turns into
:)
3.
Answer:
y= 1 and x=-2
Step-by-step explanation:
Since they both equal y, you can equal them to each other:
x + 3 = 2x + 5
Then solve:
x - x + 3 = 2x - x + 5
3 - 5 = x + 5 - 5
-2 = x
Substitute x in either equation to solve for y:
y = (-2) +3
y = 1
Or the other equation:
y = 2(-2) + 5
y = -4 + 5
y = 1
hope this helps :)
