Answer:
see the attachments below
Step-by-step explanation:
When the calculations are repetitive using the same formula, it is convenient to put the formula into a spreadsheet and let it do the calculations.
That is what was done for the spreadsheet below. The formula used is the one given in the problem statement.
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For doubling time, the formula used is the one shown in the formula bar in the attachment. (For problem 11, the quarterly value was used instead of the monthly value.) It makes use of the growth factor for the period used for the rest of the problem.
The doubling time is in years.
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The doubling time can also be found using a graphing calculator. In the second attachment, we have written a function that shows the multiplier for a given interest rate r and compounding n. The x-intercept in each case is the solution for t that makes the multiplier be 2. The steeper curve is associated with the higher interest rate.
Ask your teacher or a family member
First, you must know these formula d(e^f(x) = f'(x)e^x dx, e^a+b=e^a.e^b, and d(sinx) = cosxdx, secx = 1/ cosx
(secx)dy/dx=e^(y+sinx), implies <span>dy/dx=cosx .e^(y+sinx), and then
</span>dy=cosx .e^(y+sinx).dx, integdy=integ(cosx .e^(y+sinx).dx, equivalent of
integdy=integ(cosx .e^y.e^sinx)dx, integdy=e^y.integ.(cosx e^sinx)dx, but we know that d(e^sinx) =cosx e^sinx dx,
so integ.d(e^sinx) =integ.cosx e^sinx dx,
and e^sinx + C=integ.cosx e^sinxdx
finally, integdy=e^y.integ.(cosx e^sinx)dx=e^2. (e^sinx) +C
the answer is
y = e^2. (e^sinx) +C, you can check this answer to calculate dy/dx
Answer:
ANSWER:
450
6 of them had Blue eyes
Evan's mother drove 45 miles in total.
Jada had 15 crayons left
Amelie read 15 pages on monday.
Step-by-step explanation:
To add or subtract with powers, both the variables and the exponents of the variables must be the same. You perform the required operations on the coefficients, leaving the variable and exponent as they are.
