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ira [324]
3 years ago
5

Urgent please!!! I really don’t understand it, tysm to anyone who can answer thissss :))))

Mathematics
1 answer:
Vikki [24]3 years ago
6 0

Answer:

  • (ax + by + cz)/(a + b + c)

Step-by-step explanation:

  • Average = Sum / Number

<u>In terms of the scores we calculate the sum as:</u>

  • ax + by + cz

<u>The number is the sum of the frequencies:</u>

  • a + b + c

<u>Mean average score is:</u>

  • (ax + by + cz)/(a + b + c)
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A salesman earned commission of £2 520 for January. His rate of
Free_Kalibri [48]

Answer:

I'm sorry but I don't know English so I can't help you

Step-by-step explanation:

how do i tell you i don't know english so i can't help you friendy and well, I don't know why it won't let me upload my answer xd

6 0
3 years ago
X
Veseljchak [2.6K]
Sorry fdont really no
3 0
2 years ago
The mean of 9 observations was found to be 35. Later on, it was
USPshnik [31]

Answer:

its 42

Step-by-step explanation:

315-18+81=378

Correct mean =378/9=42

3 0
2 years ago
Suppose that you have 7 green cards and 5 yellow cards. The cards are well shuffled. You randomly draw two cards without replace
wlad13 [49]

Answer:

a. 7/22

b. 28/33

c. 7/22

d. dependent events

Step-by-step explanation:

The total number of cards is given as 7 + 5 = 12.

The probability if a card being green on the first pick, P(G) =  7/12

The probability of a card being yellow on the first pick, P(Y) = 5/12

Because there is no replacement, the card are going to be short by one card. Therefore, the second pick will be like this:

P(GG)  = ( 7/12×6/11)

P(GY) = ( 7/12 × 5/11)

P(YG) = ( 5/12×7/11)

P(RR) = ( 5/12 ×4/11)

a. P (G1 and G2) = ( 7/12×6/11)

                          = 7/22

b. P( At least one is green) = ( 7/12×6/11) +  ( 7/12 × 5/11) + ( 5/12×7/11)

                           = 28/33

c. P(G2G1)           = 7/22

d. the events are dependent. They do not give the same result.

6 0
3 years ago
Please, help it’s due today,<br> thank you
seraphim [82]
6/5 I use calculator
7 0
3 years ago
Read 2 more answers
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