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3 years ago

Which of these is a mixture?

Chemistry

2 answers:

creativ13 [48]3 years ago

8 0

Carbon Dioxide these is a mixture

beks73 [17]3 years ago

8 0

I think it's D. or B.

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Heat would best be transferred by conduction between

Maslowich

A stove and a copper pot

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3 years ago

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The atom of element has 25 electrons and 30 neutrons write down its atomic number and mass number.

den301095 [7]

Answer:

Atomic number = 25 protons

Mass number = ( 25 + 30 ) = 55

8 0

4 years ago

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Suppose a sodium hydroxide solution was standardized against pure solid primary standard grade KHP. If 0.4798 g of KHP required

Readme [11.4K]

Answer:

The NaOH solution has a molarity of 0.052 M

Explanation:

Step 1: Data given

Mass of KHP = 0.4798 grams

Volume of NaOH= 45.22 mL = 0.04522 L

Molar mass of NaOH = 40 g/mol

Molar mass of KHP = 204.22 g/mol

Step 2: Calculate moles of KHP

Moles KHP = mass KHP / Molar mass KHP

Moles KHP = 0.4798 grams / 204.22 g/mol

Moles KHP = 0.00235 moles

Step 3: Calculate moles of NaOH

KHP here acts as a mono-acid so, the number of moles of NaOH = number of moles KHP = 0.00235 moles

Step 4: Calculate molarity of NaOH

Molarity NaOH = moles NaOH / volume NaOH

Molarity NaOH = 0.00235 moles / 0.04522 L

Molarity NaOH = 0.052 M

The NaOH solution has a molarity of 0.052 M

6 0

4 years ago

Use the word react and product in a sentence that explains what a chemical reaction is

SashulF [63]

Answer:

hihihihihihihihihihihihihiihihihihihihihihihihihihiih

Explanation:

8 0

3 years ago

The activation energy for the gas phase decomposition of 2-bromopropane is 212 kJ.

irakobra [83]

The question is essentially asking for the temperature at which the rate constant will be equal to 5.06 x 10⁻³. We will be using the Arrhenius equation to solve this problem. Which is shown below:

k = Ae^(-Ea/RT)

We first must use the values provided to solve for the value of A. Once we know A, we can solve for the temperature at a given rate constant.

A = k/(e^(-Ea/RT))

A = (6.06 x 10⁻⁴)/(e^(212000/(8.314 x 683)))

A = 9.92 x 10⁻¹²

Now that we have a value for A, we can solve for the temperature that gives the provided rate constant. First we can rearrange the equation to solve for T:

k = Ae^(-Ea/RT)
lnk = lnA - Ea/RT
lnk - lnA = -Ea/RT
T = -Ea/(R(lnk - lnA))

T = -212/(0.008314)(ln(5.06 x 10⁻³) - ln(9.92 x 10⁻¹²))

T = 724 K

The rate will be equal to 5.06 x 10⁻³ at a temperature of 724 K.

7 0

3 years ago