Bleach
glass cleaner
dish-detergent
A base removes hydrogen ions from a solution
A base decreases the hydrogen ion concentration in a solution
on a ph scale something is basic if it's measured 8-14
Methane has the alkane functional group, so the name is composed of meth- for the carbon chain, and –ane for the alkane functional group
Answer:
2KHCO3+ H3PO4 arrow K2HPO4 + 2 H20 + 2C02
Explanation:
2KHCO3+ H3PO4 arrow K2HPO4 + 2 H20 + 2C02
Start with the Ks. Don't start on the right. Just balance the Ks on the left. The reason is that the CO3 is going to break down as well.
2KHCO3+ H3PO4 arrow K2HPO4 + H20 + C02
Leave the PO4 alone. Now look at the Hs that are on the right. There are 5 on the left. Leave the K2HPO4 alone. If you put a 2 in front of tthe H2O then you have a total of 5 Hs on the right.
2KHCO3+ H3PO4 arrow K2HPO4 + 2H20 + C02
There are 2 carbons on the left. You need 2 on the right.
2KHCO3+ H3PO4 arrow K2HPO4 + 2H20 + 2C02
That should do it.
Let's make a table to show balance.
Species K H C PO4- O
Left 2 5 2 1 6 from CO3^(2-)
Right 2 5 2 1 6 from H2O/CO2
False They can function as both. An example is Aluminium Oxide. These kind of substances are called "Amphoteric", they can behave as both acids and bases.
Answer:
H₂ is excess reactant and O₂ the limiting reactant
Explanation:
Based on the chemical reaction:
2H₂(g) + O₂(g) → 2H₂O
<em>2 moles of H₂ react per mole of O₂</em>
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To find limiting reactant we need to convert the mass of each reactant to moles:
<em>Moles H₂ -Molar mass: 2.016g/mol-:</em>
10g H₂ * (1mol / 2.016g) = 4.96 moles
<em>Moles O₂ -Molar mass: 32g/mol-:</em>
22g O₂ * (1mol / 32g) = 0.69 moles
For a complete reaction of 0.69 moles of O₂ are needed:
0.69mol O₂ * (2mol H₂ / 1mol O₂) = 1.38 moles of H₂
As there are 4.96 moles,
<h3>H₂ is excess reactant and O₂ the limiting reactant</h3>
