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anygoal [31]
3 years ago
9

How many joules must be added to a 1000 g iron skillet to increase its temperature

Chemistry
1 answer:
kap26 [50]3 years ago
4 0

Answer:

B) 101,025

Explanation:

1000g * 0.449 J/g Celsius * 225 Celsius = 101,025

I got 225C from 250C - 25C

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2. Natural neon exists as a mixture of 90.92% neon-20, 0.26% neon-21, and 8.82% neon-
Paul [167]
Can u please help me on mine
8 0
4 years ago
Which explains why many places on Earth experience four seasons each year rather than just
musickatia [10]

Answer:

d is the right one I think

7 0
3 years ago
How does the shape of a molecule affect the polarity of the molecule?
ruslelena [56]

Answer:

It is A

Explanation:

If you think about it, no-polar covalent bonds are in a symmetrical line, and polar bonds are on the diagonals of the center atom.

I hope I helped :)

5 0
3 years ago
Density is the ratio of a sample's mass to its volume. A bar of lead has a mass of 115.2 g. When it is submerged in 25.0 mL of w
Margarita [4]

Answer:

$10.97 \ g/cm^3$

Explanation:

Given :

Mass of a bar of lead = 115.2 g

Initial water level $\text{in the graduated cylinder}$ = 25 mL

Final water level $\text{in the graduated cylinder}$ = 35.5 mL

Difference in the water level = 35.5 - 25

                                               = 10.5 mL

                                               = 10.5 \ cm^3

We know that when a body is submerged in water, it displaces its own volume of water.

Therefore, the volume of the lead bar = volume of the water displaced = 10.5 mL  = 10.5 \ cm^3

We know that mathematically, density is the ratio of mass of body to its volume.

Density of the lead bar is given by :

$\rho =\frac{\text{mass}}{\text{volume}}$

$\rho =\frac{\text{115.2 g}}{\text{10.5 cm}^3}$

  = $10.97 \ g/cm^3$

3 0
3 years ago
5) When heated in a flame, the element Indium emits electromagnetic radiation with a distinctive indigo blue
grandymaker [24]

Answer:

\lambda=451nm

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to solve this problem by using the following equation, defined in terms of energy, Planck's constant, wavelength and speed of light:

E=\frac{hC}{\lambda }

Thus, we solve for the wavelength as shown below:

\lambda=\frac{hC}{ E}

And finally plug in the energy, Planck's constant and speed of light to obtain:

\lambda=\frac{6.6261 x 10^{-34} m^2 kg / s*3x10^8m/s}{4.405x10^{-19}m^2kg/s^2}\\\\\lambda=4.513x10^{-7}m*\frac{1nm}{10^{-9}m} \\\\\lambda=451nm

Regards!

5 0
3 years ago
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