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Hoochie [10]
3 years ago
15

DONT ANSWER IF YOU DO NOT KNOW!

Mathematics
2 answers:
Lynna [10]3 years ago
6 0

Answer:

~2.09

Step-by-step explanation:

pashok25 [27]3 years ago
3 0

Answer:

volume = 2.09 ft³

Step-by-step explanation:

volume = 1/3πr²h = 1/2(3.14)(1²)(2) = 2.09 ft³

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four of the dogs pounds are 18-19

Step-by-step explanation:

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85% of the students in the school math class have calculaters. There are 300 members in the club. How many of the members have c
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Can someone please help me with this question?
Rashid [163]

Answer:

BA ≈ 1.88

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Equality Properties

<u>Trigonometry</u>

  • [Right Triangle Trig] sin∅ = opposite over hypotenuse

Step-by-step explanation:

<u>Step 1: Define</u>

We are given a right triangle. We can use trig to find the missing length

<u>Step 2: Identify Variables</u>

<em>POV from angle C</em>

Angle = 28°

Adjacent = BA

Hypotenuse = 4

<u>Step 3: Solve for </u><em><u>BA</u></em>

  1. Substitute [sine]:                     sin28° = BA/4
  2. Isolate <em>BA</em>:                               4sin28° = BA
  3. Evaluate:                                  1.87789 = BA
  4. Rewrite:                                   BA = 1.87789
  5. Round:                                     BA ≈ 1.88
3 0
3 years ago
1. Find the cost of levelling the ground in the form of a triangle having the sides 51 m, 37 m and 20 m at the rate of ₹ 3 per m
Flauer [41]

1. Find the cost of levelling the ground in the form of a triangle having the sides 51 m, 37 m and 20 m at the rate of ₹ 3 per m².

a = 51 m, b = 37 m, c = 20 m

semiperimeter:  p = (51+37+20):2 = 54 m

Area of triangle:

A=\sqrt{p(p-a)(p-b)(p-c)}\\\\A=\sqrt{54(54-51)(54-37)(54-20)}\\\\A=\sqrt{54\cdot3\cdot17\cdot34}\\\\A=\sqrt{9\cdot2\cdot3\cdot3\cdot17\cdot17\cdot2}\\\\A=3\cdot2\cdot3\cdot17\\\\A=306\,m^2

Rate:  ₹ 3 per m².

Cost:  ₹ 3•306 = ₹ 918

2. Find the area of the isosceles triangle whose perimeter is 11 cm and the base is 5 cm.

a = 5 cm

a+2b = 11 cm  ⇒  2b = 6 cm   ⇒  b = 3 cm

p = 11:2 = 5.5

A=\sqrt{5.5(5.5-3)^2(5.5-5)}\\\\ A=\sqrt{5.5\cdot(2.5)^2\cdot0.5}\\\\ A=\sqrt{11\cdot0.5\cdot(2.5)^2\cdot0.5}\\\\A=0.5\cdot2.5\cdot\sqrt{11}\\\\A=1.25\sqrt{11}\,cm^2\approx4.146\,cm^2

3. Find the area of the equilateral triangle whose each side is 8 cm.

a = b = c = 8 cm

p = (8•3):2 = 12 cm

A=\sqrt{12(12-8)^3}\\\\ A=\sqrt{12\cdot4^3}\\\\ A=\sqrt{3\cdot4\cdot4\cdot4^2}\\\\A=4\cdot4\cdot\sqrt{3}\\\\A=16\sqrt3\ cm^2\approx27.713\ cm^2

4. The perimeter of an isosceles triangle is 32 cm. The ratio of the equal side to its base is 3 : 2. Find the area of the triangle.

a = 2x

b = 3x

2x + 2•3x = 32 cm  ⇒ 8x = 32 cm   ⇒  x = 4 cm  ⇒ a = 8 cm, b = 12 cm

p = 32:2 = 16 cm

A=\sqrt{16(16-8)(16-12)^2}\\\\ A=\sqrt{16\cdot8\cdot4^2}\\\\ A=\sqrt{2\cdot8\cdot8\cdot4^2}\\\\ A=8\cdot4\cdot\sqrt2\\\\ A=32\sqrt2\ cm^2\approx45.2548\ cm^2

8 0
3 years ago
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