Answer:
Masses of bromobenzene molecular ions will occur at 156 and 158 m/z.
Explanation:
The molecular ion peak is the signal in the mass spectrum of a compound that represents the molecular ion (denoted as M). Compounds that are composed of atoms having abundant isotope also shows M +1 and M+2 peaks (depending on the isotope).
In the given bromobenzene compound, an atom of bromine is present. The two isotopes with considerable relative abundance of Br are 79Br and 81Br with a difference of two units in their mass. This means that two molecular ion peaks with a difference of two units will appear in the mass spectrum. The mass of the whole compound is 156 amu. Hence, the molecular ion peaks will appear at 156 m/z and 158 m/z due to the two isotopes of bromine.
<h2>
Hello!</h2>
The answer is:
The third option, 79.8%
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Why?</h2>
To calculate the percent yield we need to divide the actual yield by the theoretical yield, and then, multiply it by 100 in order to find the percent.
So, we from the statement we know the following information:
Let's use the following formula and substitute the given information:
Hence, we have that the correct option is the third option, the percent yield is 79.8%.
Have a nice day!
Answer:
SN1 = a stepwise loss of a leaving group to form a carbocation followed by nucleophilic attack
Explanation:
Since 2-methyl-2-butanol is tertiary alcohol, the first step will be loss of leaving group to form a 3° carbocation which is very stable and favours SN1, followed by attack of nucleophile
