Question

A jeweler heated a sample of silver from 22.0°C to 46.0°C. The specific heat of silver is

Answer 1

The mass of the silver : 4.6 g

Further explanation  

Heat can be calculated using the formula:  

Q = mc∆T  

Q = heat, J  

m = mass, g  

c = specific heat, joules / g ° C  

∆T = temperature difference, ° C / K  

∆T = temperature difference :

$\tt 46-22=24^oC$

The specific heat of silver is  0.235 J/gºC

Q = heat = 26 J

The mass :

$\tt mass(m)=\dfrac{Q}{c.\Delta T}\\\\m=\dfrac{26}{0.235\times 24}\\\\m=4.6~g$