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bulgar [2K]
3 years ago
6

Help me find mAD please

Mathematics
1 answer:
IRISSAK [1]3 years ago
8 0

Answer:

65 degree I think

Step-by-step explanation:

Because b and c looks like it measure about the same

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Find the formula for the area A and the perimeter P of the shape shown find the area and perimeter when R is 5 cm find R when A
Ghella [55]

Answer:

1)Area; A = ¼πr²

Perimeter; P = πr/2 + 2r

2)A = 19.63 cm²

P = 17.85 cm

3) r = 8.885 cm

4) r = 14 cm

Step-by-step explanation:

This is a quadrant of a circle. Thus;

Area of a circle is πr². A quadrant is a quarter of a circle. Thus;

Formula for Quadrant Area is; A = ¼πr²

A) Perimeter of a circle is 2πr. Thus, perimeter of a quadrant is a quarter of the full circle perimeter.

Formula for the quadrant perimeter in the image given is;

P = 2πr/4 + 2r

P = πr/2 + 2r

B) When r is 5 cm;

A = ¼π(5)²

A = 19.63 cm²

P = π(5)/2 + 2(5)

P = 17.85 cm

C) when A is 100cm²:

¼πr² = 100

r² = 100 × 4/π

r² = 78.9358

r = √78.9358

r = 8.885 cm

D) when P = 50 cm.

50 = πr/2 + 2r

50 = (½π + 2)r

r = 50/(½π + 2)

r = 14 cm

6 0
3 years ago
Marco Drew 20 pictures he drew 3/4 of them in art class how many pictures did Marco draw in the art class.
Zielflug [23.3K]
He drew 15 in the art class.                     
6 0
3 years ago
Read 2 more answers
Add.<br><br> (6x3+3x2−2)+(x3−5x2−3)<br><br> Express the answer in standard form.
sergiy2304 [10]

Answer:

7x^3-2x^2-5

Step-by-step explanation:

We need to add the two terms.

(6x^3+3x^2-2)+(x^3-5x^2-3)

Solving,

Combine the like terms and adding those terms

(6x^3+3x^2-2)+(x^3-5x^2-3)\\=6x^3+3x^2-2+x^3-5x^2-3\\=6x^3+x^3+3x^2-5x^2-2-3\\=7x^3-2x^2-5

So, the answer is:

7x^3-2x^2-5

6 0
3 years ago
Can someone help me with this proof
maksim [4K]

Step-by-step explanation:

Given :

Given that lines a and b are parallel, angles 1 and 5 are congruent because they are corresponding angles, and angles 1 and 4 are congruent because they are vertical angles

To find : by which property are angles 4 and 5 congruent

Solution :

We know that if two parallel lines are cut by a transversal, then the pairs of alternate interior angles are congruent.

Also, we know that if two things are equal to the same thing then they are equal to each other . In this case, we can say that if two angles are congruent to a third angle, then they are congruent to each other. As angles 4 and 5 are both congruent to angle 1, they are congruent to each other but angles 4 and 5 are alternate interior angles. So, if parallel lines have a transversal, alternate interior angles are congruent.

8 0
2 years ago
What is the solution to this system of linear equations? Y-x=6 y+x=-10
snow_tiger [21]
\left\{\begin{array}{ccc}y-x=6\\y+x=-10\end{array}\right\ \ \ |add\ both\ sides\ of\ the\ equations\\\\2y=-4\ \ \ \ |:2\\y=-2\\\\substite\ the\ value\ of\ y\ to\ second\ equation\\\\-2+x=-10\ \ \ |+2\\x=-8

Answer:\ x=-8\ and\ y=-2

8 0
3 years ago
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