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UNO [17]
2 years ago
7

Question 7 of 15 Which is an equation of the line through (0,0) and (5,-2)? O A. y = 3 B. y = ja c. y = - 30 D. y=- Y​

Mathematics
1 answer:
9966 [12]2 years ago
6 0

Answer:

b po sana po maka tulong

Step-by-step explanation:

pa brainliest po

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HELP WILL NAME BRAINLIEST
bezimeni [28]
First, you must find the width of GHJK. Since the area of it is 84m², divide 84 by 7.
84÷7=12
So the width of GHJK is 12m.
Next, find the scale of GHJK to LMNP. Since the height of both are already available, you can divide 21÷7 to get 3
This means that to get the width of LMNP you must multiply the width of GHJK by 3.
12×3=36.
Now, to get the area of LMNP, multiply 21 by 36.

21×36=756

So, the area of LMNP is 756m². (Don't forget the units!>
5 0
2 years ago
Malik buys and sells car parts. He bought two tires for $45.00 each and later sold them for $65.00 each. He bought three rims fo
saw5 [17]
The answer is 213 dollars
4 0
3 years ago
What is needed to prove the triangles are congruent?
Stells [14]

Answer:

l ×b length ×breadth or h×b height ×breadth only this much or if you have other formula plz send me plz and what your name

4 0
2 years ago
Read 2 more answers
In ΔVWX, \text{m}\angle V = (7x-1)^{\circ}m∠V=(7x−1) ∘ , \text{m}\angle W = (4x+16)^{\circ}m∠W=(4x+16) ∘ , and \text{m}\angle X
Anika [276]

Answer:

m∠X= 22°

Step-by-step explanation:

In ΔVWX:

m∠V=(7x−1) ∘

m∠W=(4x+16) ∘ ,

m∠X=(3x−17) ∘ . Find M∠X.

Step 1

We find the variable x

The sum of angles in a triangle is 180°

Hence,

ΔVWX = m∠V + m∠W +m∠X

180° = (7x - 1)° + (4x + 16)° + (3x - 17)°

180° = 7x - 1 + 4x + 16 + 3x - 17

180° = 7x + 4x + 3x - 1 + 16 - 17

180° = 14x -2

Collect like terms

180° + 2 = 14x

182° = 14x

x = 182°/14

x = 13°

Step 2

We find m∠X

m∠X = (3x−17) ∘

x = 13

m∠X = (3 × 13 − 17)°

m∠X = (39 − 17)°

m∠X = 22°

5 0
2 years ago
Andrew
PilotLPTM [1.2K]
Let's say Bailey takes "b" days to paint it.

and Andrew takes "a" days to paint the same house.

now, Andrew is 6 times faster than Bailey, therefore, if Andrew takes "a" days to do it, Bailey takes then "6a" days, or b = 6a.

now, the year they worked together, they finished it in 7 days.

so, after 1 day then, they have only done 1/7 of the whole work.

and Andrew for one day, has done 1/a of the house, whilst Bailey has done 1/b of the house or 1/(6a).

\bf \stackrel{\textit{Andrew's rate}}{\cfrac{1}{a}}+\stackrel{\textit{Bailey's rate}}{\cfrac{1}{b}}=\stackrel{\textit{1 day of work}}{\cfrac{1}{7}}
\\\\\\
\cfrac{1}{a}+\cfrac{1}{6a}=\cfrac{1}{7}\impliedby 
\begin{array}{llll}
\textit{let's multiply all by }\stackrel{LCD}{42a}\textit{ to toss the}\\
denominators
\end{array}

\bf 42a\left( \cfrac{1}{a}+\cfrac{1}{6a} \right)=42a\left( \cfrac{1}{7} \right)\implies 42+7=6a\implies \cfrac{49}{6}=a
\\\\\\
\stackrel{days}{8\frac{1}{6}}=a
\\\\\\
\textit{how many days will it take Bailey then?}\quad b=6a
\\\\\\
b=6\cdot \cfrac{49}{6}\implies b=\stackrel{days}{49}
6 0
3 years ago
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