Answer:
The answer to your question is C = 1.116 J/g°C
Explanation:
Data
Q = 400 J
mass = 5.6 g
Temperature 1 = T1 = 23°C
Temperature 2 = T2 = 87°C
Specific heat = C = ?
Formula
Q = mC(T2 - T1)
- Solve for C
C = Q / m(T2 - T1)
- Substitution
C = 400 / 5.6 (87 - 23)
- Simplification
C = 400 / 5.6(64)
C = 400 / 358.4
- Result
C = 1.116 J/g°C
The hard parts of an organism, such as shells and bones.
I think it's physical change
