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trasher [3.6K]
2 years ago
6

Calculate the average atomic weight of Fe if abundance of isotopes 54Fe, 56Fe and 57Fe are 5%, 90%, 5% respectively. ​

Chemistry
1 answer:
kramer2 years ago
8 0

Answer:

here is the answer

tell me is it helpful

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How many millimeters of 5 M NaCl are required to prepare 1500 mL of 0.002 M NaCl?
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The correct answer is 0.6 mL.

Explanation:

We use the mathematical expression:

Ci x Vi = Cf x Vf

Where Ci is the initial concentration (5 M); Cf and Vf refers to final concentration (0.002 M) and final volume (1500 mL). With the given data, we calculate the initial volume (Vi):

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Explanation:

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