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3 years ago

What happens to the tape at the closer markers compared to the markers that are further away?

Chemistry

1 answer:

dezoksy [38]3 years ago

4 0

The tape gets smaller when it is farther away

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There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. Cac

Tanya [424]

Answer:

The equation that gives the overall equilibrium in terms of the equilibrium constants K and Ky is K1 = K^6 * Ky

Explanation:

we have the following balanced reaction:

CaC2 + 2H2O = C2H2 + Ca(OH)2

the value of K for this reaction will be equal to:

K = ([C2H2] * [Ca(OH)2])/([CaC2] * [H2O]^2)

if we multiply the reaction by the value of 6, we have:

6CaC2 + 12H2O = 6C2H2 + 6Ca(OH)2

Again, the value of K for this reaction will be equal to:

K,´ = ([C2H2] ^6 * [Ca(OH)2]^6)/([CaC2]^6 * [H2O]^12) = K^6

For the second reaction:

6C2H2 + 3CO2 + 4H2O = 5CH2CHCO2H

The value of K for this reaction:

K2 = ([CH2CHCO2H]^5)/([C2H2]^6 * [CO2]^3 * [H2O]^4)

we also have:

K1 = ([CH2CHCO2H]^5)/([C2H2]^6 * [CO2]^3 * [H2O]^16)

Thus:

K1 = K^6 * Ky

4 0

2 years ago

Calculate the mass m of 6.50 moles n of kbr m

crimeas [40]

Answer:

773.51495 grams

Explanation:

1 moles KBr to grams = 119.0023 grams

6.5*119.0023 = 773.51495 grams

8 0

2 years ago

Please help. It's for chemistry

irinina [24]

What do i help with what

3 0

2 years ago

Heat of vaporization is the amount of heat required to

deff fn [24]

I believe the answer would be c?? I’m not too sure though

5 0

2 years ago

A chemist encounters an unknown metal. They drop the metal into a graduated cylinder containing water, and find the volume chang

Mashutka [201]

Answer:

The density of the metal is 0.561 g/mL

Explanation:

The computation of the density of the metal is shown below;

As we know that

The Density of the metal is

$= \frac{mass}{volume}$

where,

Mass = 4.9g

Change in volume = 6.9 mL

Now place these values to the above formula

So, the density of the metal is

$= \frac{4.9g}{6.9mL}$

= 0.561 g/mL

Hence, the density of the metal is 0.561 g/mL

We simply applied the above formula so that the correct density could arrive

5 0

2 years ago